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Korvikt [17]
2 years ago
5

What must always be true if a covalent bond is to be polar?

Chemistry
2 answers:
scZoUnD [109]2 years ago
8 0

Answer:

If a covalent bond is polar the electronegativity difference between the elements of the compound is between 0.4 and 1.7

Explanation:

The electronegativity measures the power of an atom to attract electrons; if the electronegativity difference between the elements of the compound is big (more than 1.7) the compound will be ionic, that means, an atom or a group of atoms will give electrons and another atom of group of atoms will receive them; if the electronegativity difference is small (less than 0.4), the electrons will be shared by the atoms in a equitative way, i. e. the electrons will spend similar amount of time in the orbitals of each atom; but if the electronegativity difference is between 0.4 and 1.7  a covalent polar bond will be formed, that means valence electrons will spend more time in the orbitals of the most electronegative element.

Aleksandr [31]2 years ago
4 0
N a polar covalent bond<span>, the electrons shared by the atoms spend a greater amount of time, on the average, closer to the Oxygen nucleus than the Hydrogen nucleus. This is because of the geometry of the molecule and the great electronegativity difference between the Hydrogen atom and the Oxygen atom.</span>
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11 Which compound has the greatest percent composition by mass of sulfur?(1) BaS (3) MgS
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How many atoms of Ca are present in 80.156 grams of Ca? (4 points) 1.2044 × 1024 2.4088 × 1024 4.8270 × 1025 1.9346 × 1027
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Answer: 1.2044 × 10^24

Explanation:

1 mole of calcium is 40 gram

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms, also 1 mole of calcium is 40gram

So, 1 mole of calcium = 6.02 x 10^23 atoms

Also, 1 mole of calcium is 40gram

40 grams of calcium = 6.02 x 10^23 atoms

80.156 grams of calcium = Z atoms

To get the value of Z, cross multiply:

Z atoms x 40 grams = 6.02 x 10^23 atoms x 80.156 grams

40Z = 482.54 x 10^23

Z = (482.54 x 10^23/40)

Z = 12.06 x 10^23

Put result in standard form

Z = 1.206 x 10^24 atoms

Thus, 1.206 x 10^24 atoms of Ca are present in 80.156 grams of Ca

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