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nika2105 [10]
2 years ago
12

Of protons, neutrons and electrons which of these can never change an atom during an ordinary chemical or physical change. Expla

in why
Chemistry
1 answer:
hjlf2 years ago
6 0

Answer:

protons

Explanation:

electron number changes when the atom reacts with another atom to gain a full octet

neutron number changes when it goes through radioactive decay

but proton number never changes

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What is molarity of 3 mole of hydrochloric acid in 3L of water
Mila [183]

Answer:

1

Explanation:

6 0
2 years ago
Give the SI base unit of each of these quantities. Enter the abbreviation rather than the name of the unit. mass: __________--le
Vladimir [108]

Answer:  mass : kg, length: meter, time: second, temperature: Kelvin

Explanation:

Mass is defined as the amount of matter contained in the body.

Its units are kg, gram, milligram which are inter convertible.

S.I or M.K.S system has seven fundamental units which are used to find derived units

1) Mass - Kilogram

2) Length - meter

3) Time - Seconds

4) Electric Current - Ampere

5) Amount of substance - Moles

6) Intensity of light - Candela

7) Temperature - Kelvin

Thus SI base unit of each of these quantities are kg, meter, second, and Kelvin

4 0
2 years ago
A sample of krypton has a volume of 6.00 L, and the pressure is 0.960 atm. If the final temperature is 55.0°C, the final volume
MissTica

193.38 K was the initial temperature of the krypton.

Explanation:

Data given:

Initial volume of the krypton gas = 6 litres

initial pressure of the krypton gas = 0.960 atm

initial temperature of the krypton gas = ?

final volume of the krypton gas  = 7.70 litres

final pressure of the Krypton gas  = 1.25 atm

final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K

Applying the  Combined Gas Laws:

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Rearranging the equation:

T1  = \frac{P1V1T2}{P2V2}

Putting the value in the equation:

T1 = \frac{0.960 X 6 X 323.15}{1.25 X 7.70}

T1 = 193.38 K

Initial temperature of the krypton gas is 193.78 K

5 0
2 years ago
When a radioactive magnesium (Mg) atom decays by emitting a positron, what is the identity of the resulting atom? A. Aluminum (A
iragen [17]

The answer is: D. Sodium (Na).

Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.

There are two types of beta decay: beta minus and beta plus.

In beta plus decay (atomic number Z is decreased by one), a proton is converted to a neutron and positron and an electron neutrino, so mass number does not change.

In this example, magnesium (atomic number 12) is converted to dosium (atomic number 11).

5 0
2 years ago
Nitrosyl bromide decomposes according to the chemical equation below. 2NOBr(g) 2NO(g) + Br2(g) 1.00 atm of NOBr is sealed in a f
Andrew [12]

Given :

2NOBr(g) - -> 2NO(g) + Br2(g)

Initial pressure of NOBr , 1 atm .

At equilibrium, the partial pressure of NOBr is 0.82 atm.

To Find :

The equilibrium constant for the reaction .

Solution :

             2NOBr(g) - -> 2NO(g) + Br2(g)

t=0 s           1 atm                 0             0

t=t_{eqb}       1( 1-2x)               2x           x

So ,

1-2x=0.82\\\\x=0.09

At equilibrium :

K_{eq}=\dfrac{[NO]^2[br_2]}{[NOBr]^2}\\\\K_{eq}=\dfrac{0.18^2\times 0.9}{0.82^2}\\\\K_{eq}=0.043\ atm

Hence , this is the required solution .

3 0
2 years ago
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