Answer: mass : kg, length: meter, time: second, temperature: Kelvin
Explanation:
Mass is defined as the amount of matter contained in the body.
Its units are kg, gram, milligram which are inter convertible.
S.I or M.K.S system has seven fundamental units which are used to find derived units
1) Mass - Kilogram
2) Length - meter
3) Time - Seconds
4) Electric Current - Ampere
5) Amount of substance - Moles
6) Intensity of light - Candela
7) Temperature - Kelvin
Thus SI base unit of each of these quantities are kg, meter, second, and Kelvin
193.38 K was the initial temperature of the krypton.
Explanation:
Data given:
Initial volume of the krypton gas = 6 litres
initial pressure of the krypton gas = 0.960 atm
initial temperature of the krypton gas = ?
final volume of the krypton gas = 7.70 litres
final pressure of the Krypton gas = 1.25 atm
final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K
Applying the Combined Gas Laws:

Rearranging the equation:
T1 = 
Putting the value in the equation:
T1 = 
T1 = 193.38 K
Initial temperature of the krypton gas is 193.78 K
The answer is: D. Sodium (Na).
Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.
There are two types of beta decay: beta minus and beta plus.
In beta plus decay (atomic number Z is decreased by one), a proton is converted to a neutron and positron and an electron neutrino, so mass number does not change.
In this example, magnesium (atomic number 12) is converted to dosium (atomic number 11).
Given :
2NOBr(g) - -> 2NO(g) + Br2(g)
Initial pressure of NOBr , 1 atm .
At equilibrium, the partial pressure of NOBr is 0.82 atm.
To Find :
The equilibrium constant for the reaction .
Solution :
2NOBr(g) - -> 2NO(g) + Br2(g)
t=0 s 1 atm 0 0
1( 1-2x) 2x x
So ,

At equilibrium :
![K_{eq}=\dfrac{[NO]^2[br_2]}{[NOBr]^2}\\\\K_{eq}=\dfrac{0.18^2\times 0.9}{0.82^2}\\\\K_{eq}=0.043\ atm](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cdfrac%7B%5BNO%5D%5E2%5Bbr_2%5D%7D%7B%5BNOBr%5D%5E2%7D%5C%5C%5C%5CK_%7Beq%7D%3D%5Cdfrac%7B0.18%5E2%5Ctimes%200.9%7D%7B0.82%5E2%7D%5C%5C%5C%5CK_%7Beq%7D%3D0.043%5C%20atm)
Hence , this is the required solution .