CH3CN major species present when dissolved in water

2 answers:

5 0

The major species present when CH3CN is dissolved in water are CH3+ and CN-. It doesn't completely dissociate in water since it is not a strong acid or strong base. Only a strong acid or base will dissociate completely in water. For example HCl dissociates into H+ and Cl-, and NaOH dissociates into Na+ and OH-.

Margaret [11]1 year ago

3 0

Answer: CH₃CN and H₂O.

Explanation:

1) The spieces present in a solution may be either the molecules, in case of covalent compounds, or ions, in case of ionic compounds that dissociate (ionize).

2) Both, CH₃CN and H₂O are covalent (polar covalent) substances, so they do not ionize and the spieces in the solution are the molecules per se.

3) In solution, the molecules of H₂O will solvate the molecules of CH₃CN, meaning that H₂O molecules are able to separate the molecules of CH₃N from each other, and so every molecule of CH₃CN will end surrounded by many molecules of H₂O.

This happens because the interaction between the polar molecules of the two different compounds is strong enough to overcome the intermolecular forces between the molecules of the same compound.

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crimeas [40]

PH is calculated using <span>Handerson- Hasselbalch equation,

pH = pKa + log [conjugate base] / [acid]

Conjugate Base = Acetate (CH</span>₃COO⁻)
Acid = Acetic acid (CH₃COOH)
So,
pH = pKa + log [acetate] / [acetic acid]

We are having conc. of acid and acetate but missing with pKa,
pKa is calculated as,

pKa = -log Ka
Putting value of Ka,
pKa = -log 1.76 × 10⁻⁵

pKa = 4.75
Now,
Putting all values in eq. 1,

pH = 4.75 + log [0.172] / [0.818]

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Given reaction represents dissociation of bromine gas to form bromine atoms

Br2(g) ↔ 2Br(g)

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where n = number of moles

Δ $H^{0}f$ = enthalpy of formation

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Thus, enthalpy of dissociation is the bond energy of Br-Br = 192.9 kJ/mol

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