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Svet_ta [14]
2 years ago
5

describe the energy inputs and outputs for the campfire. Use the law of conservation of energy to construct a valid qualitative

equation that includes all the input and output energies involved.
Chemistry
1 answer:
-Dominant- [34]2 years ago
6 0

Answer:

The essence including its particular subject is outlined in the following portion mostly on clarification.

Explanation:

  • The energy throughout the campfire comes from either the wood's latent chemical energy until it has been burned to steam up and launch up across the campfire. The electricity generation for something like a campfire seems to be in the context including its potential chemical energy which is contained throughout the firewood used only to inflame the situation.
  • The energy output seems to be in the different types of heat energy radiating across the campfire, laser light generated off by the blaze, and perhaps a little number of electrical waves, registered throughout the firewood cracking whilst they combust throughout the blaze.

and,

chemical energy ⇒ heat energy + light energy + sound energy

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An alkene with the molecular formula C8H16 undergoes ozonolysis to yield a mixture of (CH3)2C=O and (CH3)3CCHO. The alkene is:
aalyn [17]

Answer:

2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Explanation:

In ozonolysis (hydrolysis step involve a reducing agent such as Zn, Me_{2}S etc.), a pi bond is broken to form ketone/aldehyde.

Ketone is formed from di-substituted side of double bond and aldehyde is formed from mono-substituted side of double bond.

Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.

Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.

Here, 2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Reaction steps are shown below.

8 0
2 years ago
Aurelia dropped a piece of metal into a beaker, and then she added acid to it. She saw colorless bubbles rising from the metal.
timofeeve [1]

Answer:

Chemical change

Explanation:

From all indicators, Aurelia is seeing a chemical change occurring in the reaction here.

A chemical change is a change in which new substances are produced. For every chemical change:

  • they are not easily reversible
  • they lead to production of new kinds of substances
  • involves mass change
  • require considerable amount of energy.

We start off and end with:

         Metal   +     Acid →     Black metal     +    rising gaseous bubbles

Clearly, it is shown that new products are formed and this reaction is impossible to reverse in order to get the reactants back.

This is a typical chemical change.

4 0
2 years ago
Read 2 more answers
A sixth grade teacher takes students on a field trip to the beach. One student finds several pebbles that have a rounded shape a
Fittoniya [83]

Answer:

C: The shape of the pebbles is a result of weathering and deposition

Explanation:

For the several pebbles to have a rounded shape and smooth to the touch, it will undergo weathering and deposition. This is because weathering involves breaking down of rocks and creating new sediments. This weathering could be either chemical weathering or physical weathering where Chemical weathering is the decomposition of rocks which are caused by chemical reactions and which result in formation of new compound while physical weathering is the breakdown of rocks into smaller pieces. On the other hand, deposition occurs when the agents of erosion such as wind or water deposit sediments from one spot to another which in turn changes the shape of the land.

Thus, the shape of the pebbles are as a result weathering of the parent rocks and from deposition.

7 0
2 years ago
50 mL of CH3CH2Br (bromoethane) and 50 mL of water are poured into a separatory funnel. Bromoethane is a water‑insoluble compoun
umka21 [38]

Answer:

See explanation below

Explanation:

In this case, we can explain this in a very basic way.

We know that heavier objects will go always at the bottom when we are carrying two objects, one heavier than the other right?

In the same manner works the density of two liquids. In this case, we have a mix of water and bromoethane. Bromoethane is an organic compound and it's less polar than water which is extremely polar. When we mix these two liquids, we can see that both of them are insoluble, so no matter how much we shake the funnel, the liquids will not mix to form a solution.

Instead of that, both of them will be in the funnel, and they'll be gradually separating into two layers. The bromoethane has a higher density than water, this means that in the bottom layer we will have the bromoethane and in the top layer we will have the water.

In case you are wondering what happens if we added water first and then, the bromoethane?, it will happen the same, it does not matter the order you add the liquid, because density here is a very important factor, so when the water is added no matter which position, it will go to the top layer after the bromoethane is added.

Now when the hexane is added, it will form now three layers, and again, density plays an important factor. The higher density will go to the bottom, and the lowest to the top.

In this case, the order of layer will be:

Top layer: hexane (d = 0.66 g/mL)

Middle layer: water (d = 1 g/mL)

Bottom layer: bromoethane (d = 1.46 g/mL)

Hope this helps

6 0
2 years ago
Identify structure(s) for all constitutional isomers with the molecular formula C4H8 that have one double bond. Select all that
Alchen [17]

Answer:

a) But-1-ene

b) E-But-2-ene

c) Z-But-2-ene

d) 2-Methylpropene

Explanation:

In this case, if we want to draw the <u>isomers</u>, we have to check the<u> formula </u>C_4_H8 in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain <u>But-1-ene.</u>

<u />

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain <u>Z-But-2-ene</u>. When the methyls groups are placed on opposite sides we will obtain <u>E-But-2-ene.</u>

<u />

Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain <u>2-Methylpropene.</u>

<u />

See figure 1 to further explanations.

I hope it helps!

<u />

<u />

8 0
2 years ago
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