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Elanso [62]
1 year ago
15

A wave hits a wall as shown. A brick wall with a green arrow pointing to the wall from below and right at a shallow angle. Anoth

er green arrow starts where the first arrow touched the wall and goes up and left at the same shallow angle. As the wave interacts with a wall, which kind of wave interaction is shown?
Chemistry
2 answers:
drek231 [11]1 year ago
4 0

Answer:

reflection

Explanation:

its on edg.

Dominik [7]1 year ago
3 0

Answer:

A wave reflection interaction (reflected by the wall)

Explanation:

In a reflection, the propagating wave is bounced off the reflecting surface because the medium of the surface prevents the propagation of the wave through it, such that wave is redirected at an angle equal to the angle of incident on the reflecting surface

Reflection takes place with the different forms of waves, such as sound wave, water waves, and light wave

The objects around us are seen with the aid of reflection of light from a light source such that the reflected light enters our eyes after being reflected on the surface of the object, and the object is seen.

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A 0.300 g piece of copper is heated and fashioned into a bracelet. The amount of energy transferred by heat to the copper is 66,
Alja [10]

Answer:

X=600 degrees celsius

Explanation:

We can evaluate by using the equation ==> Q=m(c)(delta T)

-We know the mass is 0.3 g

-Q= 66,300 J

-C= 390 j/g 0C

-Therefore, we need to solve for delta T (which will be represented by x)

 Q= mct

66,300 J= 0.3 g (390 J/g 0C) (t)

The unit of measurement (g-grams) can be crossed out on the left side of our expression.

66,300 J=0.3(390 J 0C) (t)

-If we convert into a proportional relationship:

66,300 J                117 J/0C x

------------       =        -----------

117 J/0C                 117 J/0C

-Joules on both sides can be crossed off

*117 J/0C came from the product in terms of 0.3(390 J 0C)

*If we find the quotient of 66,300 J and 117 J/0C, we get 566.6 repeating

-You may keep the answer as it is, although for simplicity reasons, we can round to the nearest hundred.

-Therefore, x=600.

-----Remember, x represented the delta t in our equation. (I made notice of that when evaluating).

Hope this helps! :)

3 0
1 year ago
What is the formal charge on the nitrogen in hydroxylamine, h2noh?
andrew11 [14]
<h3>Answer:</h3>

             Formal Charge on Nitrogen is "Zero".

<h3>Explanation:</h3>

Formal Charge on an atom in molecules is calculated using following formula;

Formal Charge  =  [# of Valence e⁻s] - [e⁻s in lone pairs + 1/2 # of Bonding e⁻s]

As shown in attached picture of Hydroxylamine, Nitrogen atom is containing two electrons in one lone pair of electrons and six electrons in three single bonds with two hydrogen and one oxygen atom respectively.

Hence,

                                  Formal Charge  =  [5] - [2 + 6/2]

                                  Formal Charge  =  [5] - [2 + 3]

                                  Formal Charge  =  5 - 5

                                  Formal Charge  =  0    (zero)

Hence, the formal charge on nitrogen atom in hydroxylamine is zero.

5 0
1 year ago
Methyl tertiary-butyl ether (MTBE) is an organic compound that has been in use since the late 1970s. Read the article to learn m
tamaranim1 [39]
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7 0
2 years ago
Gino made a table to describe parts of the electromagnetic spectrum. A 3-column table with 4 rows. The first column labeled wave
IgorC [24]

Answer:

D. Ultraviolet light should have a short wavelength, not a long wavelength.

Explanation:

just took the quiz on Ed

7 0
2 years ago
Read 2 more answers
The laser in a 3D printer uses light with a frequency of 3.844 × 1014 Hz. Calculate the wavelength of this light in nm. Show all
Natali5045456 [20]

Answer:

The wavelength of this light is 780.4 nm.

Explanation:

Given that,

The frequency of laser light, f=3.844 \times 10^{14}\ Hz

We need to find the wavelength of this light.

We know that,

c=f\lambda

Where

\lambda is the wavelength of light

So,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3.844 \times 10^{14}}\\\\=7.804\times 10^{-7}\ m\\\\=780.4\ nm

So, the wavelength of this light is 780.4 nm.

5 0
1 year ago
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