Answer : The grams of consumed is, 89.6 grams.
Solution : Given,
Mass of = 265 g
Molar mass of = 80 g/mole
Molar mass of = 28 g/mole
First we have to calculate the moles of .
The given balanced reaction is,
from the reaction, we conclude that
As, 1 mole of produces from 1 mole of
So, 3.2 moles of produces from 3.2 moles of
Now we have to calculate the mass of
Therefore, the grams of consumed is, 89.6 grams.
<u>Answer:</u> The equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.
<u>Explanation:</u>
We are given:
Initial concentration of sulfur dioxide = 0.500 M
Initial concentration of nitrogen dioxide = 0.500 M
Initial concentration of sulfur trioxide = 0.00500 M
Initial concentration of nitrogen monoxide = 0.00500 M
The chemical reaction follows:
<u>Initial:</u> 0.500 0.500 0.005 0.005
<u>At eqllm:</u> 0.500-x 0.500-x 0.005+x 0.005+x
The expression of equilibrium constant for the above reaction follows:
We are given:
Putting values in above equation, we get:
Neglecting the value of x = 1.37, because change cannot be greater than the initial concentration
So, equilibrium concentration of sulfur dioxide =
Equilibrium concentration of nitrogen dioxide =
Equilibrium concentration of sulfur trioxide =
Equilibrium concentration of nitrogen monoxide =
Hence, the equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.