No of moles of naoh = 2.40 ÷ (23+16+1) = 0.06mol
no of moles of na2co3 = 0.06 ÷ 2 = 0.03mol
mass of na2co3 = 0.03 × (23×2+12+16×3) = 0.03 × 106 = 3.18g
The answer is isotonic solution. These are solutions where
the solute concentration in the solution and inside the cells are levelled and consequently
water flows consistently. When red blood cells are positioned in an isotonic
solution the cells would always stay the same.
The hydroxide concentration is written as [OH-]. A useful equation is that pH + pOH = 14. Since the pH is 4, the pOH must be 10. To get [OH-], again take the neg. anti-log of both sides: - anti log (pOH-) = - antilog(10) ---> [OH-]=1 x 10^-10 M or 1 x 10^-10 moles [OH-] per liter solution (in this case, lake).
The hydroxide ion concentration describe in question 3 is 10-10 M
Answer:
From highest to lowest:
butanol: 117.7 degree Celsius
butanone: 79.64 degree Celsius
diethyl ether: 34.6 degree Celsius
n-butane: -0.4 degree Celsius
