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Margaret [11]
2 years ago
15

What element speed of sound is 323 m/s?​

Chemistry
1 answer:
Pepsi [2]2 years ago
3 0

Answer:

Speed of Sound

Explanation:

Speed of sound, fluid phases

 

m/s

notes

WEL 206  

use 323 27 °C

CRC 323 27 °C

WEL 319

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Explain on the chemical structural basis why the products of the saponification reaction are soluble in water while the starting
aev [14]

Answer:

The description is outlined in subsection downwards and according to the query given.

Explanation:

  • Saponification seems to be a procedure that requires the conversion or transformation of fat, grease, or lipid by either the intervention of heating a mixture of aqueous alkali towards soap as well as an alcoholic. Soaps contain fatty acid salts, however, mono-fatty acids contain carbon atoms, such as sodium palmitate. Therefore, throughout the water, individuals were indeed soluble.
  • However, on another hand, owing to large hydrocarbon strings, triglycerides do not partake in hydrogen bonding. Therefore in water, they aren't dissolved.
7 0
1 year ago
Convert 1.71 × 1024 atoms of carbon to moles of carbon.
beks73 [17]
You need to use Avogadro's constant to convert from atoms of carbon to moles of carbon.

1.71*10^24 atoms C * (1 mole/6.022*10^23 atoms) = 2.84 moles of carbon
7 0
2 years ago
Be sure to answer all parts. ΔH o f of hydrogen chloride [HCl(g)] is −92.3 kJ/mol. Given the following data, determine the ident
Akimi4 [234]

Answer:

NH₄Cl(s) → NH₃(g) + HCl(g)

ΔH°rxn 74,89 kJ/mol

Explanation:

The change in enthalpy of formation (ΔHf) is defined as the change in enthalpy in the formation of a substance from its constituent elements. For HCl(g):

<em>(1) </em>¹/₂H₂(g) + ¹/₂ Cl₂ → HCl(g) ΔH = -92,3 kJ/mol

It is possible to sum ΔH of different reactions to obtain ΔH of a global reaction (Hess's law).

For the reactions:

<em>(2) </em>N₂(g) + 4H₂(g) + Cl₂(g) → 2NH₄Cl(s) ΔH°rxn = −630.78 kJ/mol

<em>(3)</em> N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

The sum of -(2) + (3) gives:

<em>-(2) </em>2NH₄Cl(s) → N₂(g) + 4H₂(g) + Cl₂(g) ΔH°rxn = +630.78 kJ/mol

<em>(3)</em> N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

<em>-(2) + (3) </em>2NH₄Cl(s) → 2NH₃(g) + H₂(g) + Cl₂(g)

ΔH°rxn = +630.78 kJ/mol −296.4 kJ/mol = +334,38 kJ/mol

Now, the sum of -(2) + (3) + 2×(1)

<em>-(2) + (3) </em>2NH₄Cl(s) → 2NH₃(g) + H₂(g) + Cl₂(g) ΔH°rxn = +334,38 kJ/mol

<em>2×(1)  </em>H₂(g) + Cl₂(g)→ 2HCl(g) ΔH = 2×-92,3 kJ/mol

<em>-(2) + (3) + 2×(1) </em>2NH₄Cl(s) → 2NH₃(g) + 2HCl(g)

ΔH°rxn = +334,38 kJ/mol + 2×-92,3 kJ/mol = 149,78 kJ/mol

The reaction of:

<em>NH₄Cl(s) → NH₃(g) + HCl(g)</em>

<em>Has ΔH°rxn = 149,78kJ/mol / 2 = 74,89 kJ/mol</em>

I hope it helps!

8 0
1 year ago
Consider the element in the periodic table that is directly to the right of the element identified in part (a). Would the 1s pea
astraxan [27]

The question is incomplete. Here is the complete question.

The photoelectron spectroscopy is shwon below.

(a) Based on the photoelectron spectrum, identify the unknown element and write its electron configuration.

(b) Consider the element in the periodic table that is directly to the right of the element identified in part (a). Would the 1s peak of this element appear to the left of, the right of, or in the same position as the 1s peak of the element in part (a)? Explain your reasoning.

Answer and Explanation: <u>Photoelectron</u> <u>Spectroscopy</u> is a method of determinining the relative energy of electrons in atoms and molecules.

It is based on the <em>photoelectric effect: </em>when a radiation energy incides on a substance, an electron is ejected from it. If we know the kinetic energy of the ejected electron, known as photoelectrons, and the energy of the incident radiation, it is possible to find the energy of the electron in the substance.

The energy needed to eject an electron from the sample is called <em>Binding Energy</em> and in an atom, depends on which shell the electron is: valence eletrons (outermost shell), binding energy is lower; core eletrons (innermost shell), binding energy is highest.

In the graph, vertical axis shows 5 peaks for different energies. The peak closer to the origin, the leftmost peak, correspond to the 1s subshell, since their are closest to the nucleus, and so, has the highest binding energy.

Following from left to the right, we noticed:

  • First, second and fourth peaks has the same height;
  • Third peak's height is 3x higher than 1st, 2nd and 4th;
  • Fifth peak is one unit higher than first, second and fourth;

(a) Then, we can conclude the eletron configuration of the element is

1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{3}

which is Phosphorus with atomic number of 15.

(b) The element to the right of element P is Sulfur (S). The peak 1s of sulfur will appear in the same position as the 1s peak of Phosphorus, because the elements in the Periodic Table are grouped according to certain properties. Elements in the same horizontal line are elements in the same period, which one of the characteristics is they have the same total number of electron shells.

4 0
1 year ago
Determine the type of each chemical equation describing a precipitation reaction. C a 2 + ( a q ) + S O 4 2 − ( a q ) ⟶ C a S O
Zepler [3.9K]

Answer:

C a B r 2 ( a q ) + N a 2 S O 4 ( a q ) ⟶ 2 N a B r ( a q ) + C a S O 4 ( s )

Explanation:

A precipitation reaction is a type of displacement reaction which a precipitate forms. The precipitate would be in the solid state, different from the other products so it can be separated or removed from the reaction.

C a 2 + ( a q ) + S O 4 2 − ( a q ) ⟶ C a S O 4 ( s )

This is wrong because  C a S O 4  is the the only product formed.

C a B r 2 ( a q ) + N a 2 S O 4 ( a q ) ⟶ 2 N a B r ( a q ) + C a S O 4 ( s )

This is the correct option, The precipitate is C a S O 4.

C a 2 + ( a q ) + 2 B r − ( a q ) + 2 N a + ( a q ) + S O 4 2 − ( a q ) ⟶ 2 N a + ( a q ) + 2 B r − ( a q ) + C a S O 4 ( s )

This is the ionic equation for the precipitation reaction

8 0
1 year ago
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