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ale4655 [162]
1 year ago
11

You look at the label on a container of shortening and see the words "hydrogenated vegetable oil." this means that during proces

sing, the number of carbon–carbon double bonds in the oil was decreased. what is the result of decreasing the number of double bonds?
Chemistry
2 answers:
Arisa [49]1 year ago
6 0
  • Increase in melting point;
  • Trans- arrangements of side chains around double bonds that remains in the hydrogenated fat.

Explanation:

Vegetable oil contain significantly more double bonds than animal fat such as butter does. Unlike carbon-carbon single bonds, structures connected to carbon-carbon double bonds are unable to rotate around the bonding axis. As a result, molecules rich in double bonds aren't as malleable or stack as tightly as those with a small number of double bonds do. The spacy molecular configuration hinders the formation of intermolecular forces, such that in nature in comparison with animal fats, vegetable <em>oils</em> tend to demonstrate lower melting points.

Hydrogenating vegetable oils reduce the number of double bonds per molecule while attaching extra hydrogen atoms to carbon atoms that used to form double bonds. This process would increase the strength of intermolecular interaction, hence raising the melting point.

The hydrogenation process does not necessary convert <em>all</em> double bonds to single bonds; some double bonds remains in the molecule, preventing the rotation of structures on their sides. Double bonds in unprocessed fatty acids tend to be of the cis- configuration, with hydrogen atoms connected to the same side of the carbon-carbon double bond. The high temperature involved in the hydrogenation process (around 90 degrees Celsius) can trigger the flipping of atoms connected to these double bonds to produce trans- fatty acids with hydrogen atoms bonded to opposite sides of the double bond.

Leya [2.2K]1 year ago
5 0
  • Increase in melting point;
  • Trans- arrangements of side chains around double bonds that remains in the hydrogenated fat.

Explanation:

Vegetable oil contain a larger ratio of double bonds among all its carbon-carbon bonds than animal fat such as butter does. Unlike carbon-carbon single bonds, structures connected to carbon-carbon double bonds are unable to rotate around the bonding axis. As a result, molecules rich in double bonds aren't as malleable or stack as tightly as those with a smaller number of double bonds do. The spacy molecular configuration hinders the formation of intermolecular forces, such that in nature in comparison with animal fats, vegetable <em>oils</em> tend to demonstrate lower melting points.

Hydrogenating vegetable oils reduce the number of double bonds per molecule while attaching extra hydrogen atoms to carbon atoms that used to form double bonds. This process would increase the strength of intermolecular interaction, hence raising the melting point.

The hydrogenation process does not necessary convert <em>all</em> double bonds to single bonds; some double bonds remains in the molecule, preventing the rotation of structures on their sides. Double bonds in naturally-occuring fatty acids tend to be of the cis- configuration, with hydrogen atoms connected to the same side of the carbon-carbon double bond. The high temperature involved in the hydrogenation process (around 90 degrees Celsius) can trigger the flipping of atoms connected to these double bonds to produce trans- fatty acids with hydrogen atoms bonded to opposite sides of the double bond.

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Larisa pumps up a soccer ball until it has a gauge pressure of 61 kilopascals. The volume of the ball is 5.2 liters. The air tem
Nuetrik [128]
<h3>Answer:</h3>

B.  0.33 mol

<h3>Explanation:</h3>

We are given;

Gauge pressure, P = 61 kPa (but 1 atm = 101.325 kPa)

                               = 0.602 atm

Volume, V = 5.2 liters

Temperature, T = 32°C, but K = °C + 273.15

thus, T = 305.15 K

We are required to determine the number of moles of air.

We are going to use the concept of ideal gas equation.

  • According to the ideal gas equation, PV = nRT, where P is the pressure, V is the volume, R is the ideal gas constant, (0.082057 L.atm mol.K, n is the number of moles and T is the absolute temperature.
  • Therefore, to find the number of moles we replace the variables in the equation.
  • Note that the total ball pressure will be given by the sum of atmospheric pressure and the gauge
  • Therefore;
  • Total pressure = Atmospheric pressure + Gauge pressure  

       We know atmospheric pressure is 101.325 kPa or 1 atm

Total ball pressure = 1 atm + 0.602 atm

                               = 1.602 atm

That is;

PV = nRT

n = PV ÷ RT

therefore;

n = (1.602 atm× 5.2 L) ÷ (0.082057 × 305.15 K)

  = 0.3326 moles

  = 0.33 moles

Therefore, there are 0.33 moles of air in the ball.

4 0
2 years ago
A 5-ounce cup of raspberry yogurt contains 5.0 g of protein, 3.0 g of fat, and 13.3 g of carbohydrate. The fuel values for prote
castortr0y [4]

Answer:

as it has 17000 joules and 1 calorie has 4184 joules, this yogurt serving has 4.06 calories

6 0
1 year ago
Item 5 A solution of methanol, CH3OH, in water is prepared by mixing together 128 g of methanol and 108 g of water. The mole fra
Basile [38]

Answer:

Mole fraction of methanol will be closest to 4.

Explanation:

Given, Mass of methanol = 128 g

Molar mass of methanol = 32.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{128\ g}{32.04\ g/mol}

Moles\ of\ methanol = 3.995\ mol

Given, Mass of water = 108 g

Molar mass of water = 18.0153 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{108\ g}{18.0153\ g/mol}

Moles\ of\ water= 5.995\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ methanol=\frac {n_{methanol}}{n_{methanol}+n_{water}}

Mole\ fraction\ of\ methanol=\frac{3.995}{3.995+5.995}=0.39989

<u>Mole fraction of methanol will be closest to 4.</u>

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Burka [1]

Better than i am and very precice


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2 years ago
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