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Katarina [22]
2 years ago
6

The table below provides some information about an unidentified element. Based on this information, the unidentified element is

best classified as which of the following?
A) a metal in group 1
B) a metal in group 14
C) a nonmetal in period 4
D) a metalloid in period 5

Chemistry
1 answer:
Leona [35]2 years ago
5 0

In the physical properties, it is mentioned that the element has 4 valence electrons. The elements in the periodic table are arranged such that, the number of valence electrons present in the neutral atoms belonging to a particular group  is equal to the group number.

Thus, the unidentified element can be best classified as a nonmetal in period 4

Ans C)

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Select the valid ways to make an ammonia/ammonium buffer for use in the laboratory. Mix equal volumes of 1 M NH3 and 0.01 M NH 4
mrs_skeptik [129]

Answer:

The answer is "Option b and Option c".

Explanation:

This buffer is a buffer of ammonia and ammonium ion. Thus it requires the solution NH_3 \ \ and \ \ NH_4^{+}.

In point 1:

The solution containing NH_3 \ \ and \ \ NH_4^{+} at 1M concentration would be given by mixing the two solutions. Thus, this buffer is a legitimate route.

In point 2:

It gives the ions you want but they are not the same.

In point 3:

1 M NH_3 and 1 MHCl volume would not produce the same NH_3 \ \ and \ \ NH_4^{+} concentrations. Therefore, this buffer isn't a valid route.

In point 4:

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1 year ago
A Gas OCCUPIES 525ML AT A PRESSURE OF 85.0 kPa WHAT WOULD THE VOLUME OF THE GAS BE AT THE PRESSURE OF 65.0 kPa
german

Boyle's law of ideal gas: This law states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Acc to this law we can write the relation of pressure and volume as:

PV=Constant

That means:

P_{1}V_{1}=P_{2}V_{2}

From that equation we can calculate Volume of gas at a certain pressure:

P₁=Initial pressure

V₁=Initial volume

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Here P₁, initial pressure is given as 85.0 kPa

V₁, initial volume is given as 525 mL

P₂, final pressure is 65.0 kPa

P_{1}V_{1}=P_{2}V_{2}

so,

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Volume of gas will be 686 mL.

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