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Afina-wow [57]
2 years ago
5

Identify the type of solid from the description. Select from the following choices: metallic solid, network solid, molecular sol

id, ionic solid, or amorphous solid. a. This solid is very hard and has a very high melting point. (1 point) b. This solid conducts heat well and has a range of hardness. (1 point) c. This solid is hard and depends on charge attractions to hold it together. (1 point)
Chemistry
1 answer:
scZoUnD [109]2 years ago
4 0

First of all, there are five types of solid materials:  

Metallic solids which are solids composed of metal atoms that are held together by metallic bonds.

Network solid is a chemical compound in which the atoms are bonded by covalent bonds in a continuous network extending throughout the material.

Molecular solid is a solid consisting of discrete molecules.  

Ionic solid is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding.  

Amorphous solid is non-crystalline solid that lacks the long-range order that is characteristic of a crystal.

Now, after the defined all the types of solid materials in the equation lets to solve it.  

A. the answer is the network solids, because covalent bonds are relatively strong, covalent are typically characterized by hardness, strength, and high melting points.

B. the answer is the metallic solids, due to that heat conduction occurs when a substance is heated and the particles will gain more energy vibrating more. These molecules then bump into nearby particles and transfer some of their energy to them and in metals this process have a higher probability than in the case of other solids due to the nature of the chemical bonds. It also has a range of hardness due to the strength of metallic bonds which varies dramatically.

C. the answer is the ionic solid; due to positive and negative ions which are  bonded to form a crystalline solid held together by charge attractions.

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A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine
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The final volume of the sample of gas V_{2} = 0.000151 m^{3}

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Initial volume V_{1} = 200 ml = 0.0002 m^{3}

Initial temperature T_{1} = 296 K

Initial pressure P_{1} = 101.3 K pa

Final temperature T_{2} = 336 K

Final pressure P_{2} =  K pa

Relation between P , V & T is given by

P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation we get

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2 years ago
A student runs an experiment in the lab and then uses the data to prepare an Arrhenius plot of the natural log of the rate const
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CaCl_2~->~Ca^+^2~+~2Cl^-

The cation would be Ca^+^2 and the anion is Cl^-. So, we will have an <u>ionic compound.</u>

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In this molecule, we have single bonds between carbon and hydrogen. The electronegativity difference between C and H are not high enough to produce ions. So, with this in mind, we will have covalent bonds. This is the main characteristic of <u>organic compounds. </u> (See figure 1)

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