Question

Consider the reaction below. 2Al2O3 4Al + 3O2 How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed? 17.7 mol 19.9 mol 39.8 mol 53.0 mol

Answer 1

 The moles  of  oxygen  that are produced when 26.5 mol  of Al2O3  decomposes  is  39.8 mol

calculation

2Al2O3  + 4Al +3 O2

•  use the mole  ratio  of Al2O3  to O2  to determine the moles of  O2.

• that is   from  the  equation above the mole ratio of Al2O3 : O2 is 2:3  

• the moles of O2  is therefore=n 26.5 mol  x3/2= 39.8  moles

Answer 2

Answer : The number of moles of oxygen produced are, 39.8 mole

Solution : Given,

Moles of aluminium oxide = 26.5 mole

The given balanced chemical reaction is,

$2Al_2O_3\rightarrow 4Al+3O_2$

From the balanced chemical reaction, we conclude that

As, 2 moles of aluminium oxide decomposes to give 3 moles of oxygen

So, 26.5 moles of aluminium oxide decomposes to give $\frac{3}{2}\times 26.5=39.75=39.8$ moles of oxygen

Therefore, the number of moles of oxygen produced are, 39.8 mole