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ipn [44]
2 years ago
12

Consider the reaction below. 2Al2O3 4Al + 3O2 How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decompos

ed? 17.7 mol 19.9 mol 39.8 mol 53.0 mol
Chemistry
2 answers:
Aloiza [94]2 years ago
3 0

 The moles  of  oxygen  that are produced when 26.5 mol  of Al2O3  decomposes  is  39.8 mol


<u>calculation</u>

<u> </u> 2Al2O3  + 4Al +3 O2


  •  use the mole  ratio  of Al2O3  to O2  to determine the moles of  O2.
  • that is   from  the  equation above the mole ratio of Al2O3 : O2 is 2:3  
  • the moles of O2  is therefore=n 26.5 mol  x3/2= 39.8  moles
Anon25 [30]2 years ago
3 0

Answer : The number of moles of oxygen produced are, 39.8 mole

Solution : Given,

Moles of aluminium oxide = 26.5 mole

The given balanced chemical reaction is,

2Al_2O_3\rightarrow 4Al+3O_2

From the balanced chemical reaction, we conclude that

As, 2 moles of aluminium oxide decomposes to give 3 moles of oxygen

So, 26.5 moles of aluminium oxide decomposes to give \frac{3}{2}\times 26.5=39.75=39.8 moles of oxygen

Therefore, the number of moles of oxygen produced are, 39.8 mole

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