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sashaice [31]
2 years ago
12

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [

Co3+]= 0.190 M , [Co2+]= 0.205 M , and [Cl−]= 0.144 M , and the pressure of Cl2 is PCl2= 7.30 atm ?
Chemistry
1 answer:
Nesterboy [21]2 years ago
6 0

Answer:

Ecel =0,04 V

Explanation:

Apply the Nerst equation,

Ecel= Ecelº - (RT/nF)*lnQ

where R=8,314 J/molK, T=25ºC=298K and F =96 485 Coulombs/mol e- and n=number of moles of electrons transferred in the balanced equation. Q is cocient of products and reactives power to respective coefficients, if is a gas apply partial pressure

Write the semiequation redox and verify the numbers of electron for balance. In this case you don't need to change nothing

2Cl−(aq)→Cl2(g) + 2e-

<u>2CO3+(aq) + 2e-→2CO2+(aq)</u>

2Cl−(aq) + <u>2CO3+(aq) </u>→<u>2CO2+(aq) + </u>Cl2(g)

Hence

Ecel= 0.483 V -  0.013Ln ([CO2+]^2*PCl2] / [CO3+]^2*[Cl-]^2)

Ecel= 0.483 V -  0.013Ln ([0.205]^2 * 7.3] / [0.19]^2*[0.144]^2)

Ecel =0,04 V

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                    1)  Stability of Carbocation:
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An old sample of concentrated sulfuric acid to be used in the laboratory is approximately 98.1 percent h2so4 by mass. calculate
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                        mass = density x volume

                       mass = (1.83 g/mL) x (100 mL) = 183 grams

Then, we calculate for the mass H2SO4 given the percentage.
                   
                      mass of H2SO4 = (183 grams) x (0.981) = 179.523 grams

Calculate for the number of moles of H2SO4,
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Molarity:
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koban [17]

Answer:

The atomic mass of second isotope is 7.016

Explanation:

Given data:

Average Atomic mass of lithium = 6.941 amu

Atomic mass of first isotope = 6.015 amu

Relative abundance of first isotope = 7.49%

Abundance of second isotope = ?

Atomic mass of other isotope = ?

Solution:

Total abundance = 100%

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percentage abundance of second isotope = 92.51%

Now we will calculate the mass if second isotope.

Average atomic mass of lithium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

6.941 = (6.015×7.49)+(x×92.51) /100

6.941 =  45.05235 + (x92.51) / 100

6.941×100 = 45.05235 + (x92.51)

694.1 - 45.05235   = (x92.51)

649.04765 = x 92.51

x = 485.583 /92.51

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The atomic mass of second isotope is 7.016

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2 years ago
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