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BigorU [14]
2 years ago
10

The information below describes a redox reaction. 3 equations: First: upper C r superscript 3 plus (a q) plus 2 upper C l supers

cript minus (a q) right arrow upper C r (s) plus upper C l subscript 2 (g). Second: 2 upper C l superscript minus (a q) right arrow upper C l subscript 2 (g) plus 2 e superscript minus. Third: upper Cr superscript 3 plus (a q) plus 3 e superscript minus right arrow upper C r (s). What is the final, balanced equation for this reaction? 2 upper C r superscript 3 plus (a q) plus 6 upper C l superscript minus (a q) right arrow 2 upper C r (s) plus 3 upper C l subscript 2 (g). 2 upper C r superscript 3 plus (a q) plus 2 upper C l superscript minus (a q) plus 6 e superscript minus right arrow upper C l subscript 2 (g) plus 2 upper C r (s). Upper C r superscript 3 plus (a q) plus 6 upper C l superscript minus (a q) plus 3 e superscript minus right arrow 2 upper r (s) plus 3 upper C l subscript 2 (g). Upper C r superscript 3 plus (a q) plus 2 upper C l superscript minus (a q) right arrow upper C r (s) plus upper C l subscript 2 (g).
Chemistry
1 answer:
Marrrta [24]2 years ago
7 0

Answer:

A.

Explanation:

I just took the quiz.

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12. The vapor pressure of water at 90°C is 0.692 atm. What is the vapor pressure (in atm) of a solution made by dissolving 3.68
luda_lava [24]

Answer : The vapor pressure (in atm) of a solution is, 0.679 atm

Explanation : Given,

Mass of H_2O = 1.00 kg = 1000 g

Moles of CsF = 3.68 mole

Molar mass of H_2O = 18 g/mole

Vapor pressure of water = 0.692 atm

First we have to calculate the moles of H_2O.

\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{1000g}{18g/mole}=55.55mole

Now we have to calculate the mole fraction of H_2O

\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }CsF}=\frac{55.55}{55.55+3.68}=0.938

Now we have to partial pressure of solution.

According to the Raoult's law,

P_{Solution}=X_{H_2O}\times P^o_{H_2O}

where,

P_{Solution} = vapor pressure of solution

P^o_{H_2O} = vapor pressure of water = 0.692 atm

X_{H_2O} = mole fraction of water = 0.938

P_{Solution}=X_{H_2O}\times P^o_{H_2O}

P_{Solution}=0.938\times 0.692atm

P_{Solution}=0.649atm

Therefore, the vapor pressure (in atm) of a solution is, 0.679 atm

5 0
2 years ago
Which of the following will ammonium ion form an insoluble salt? 4/16 a. chloride b. sulfate c. sulfate and carbonate d. carbona
Darina [25.2K]

Answer:

e

Explanation:

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Approximately ____ days have passed when 20% of Cobalt (Co) remains? A) 19 B) 20 C) 21 D) 29
Brums [2.3K]
The answer to this is A i think.
3 0
2 years ago
The decomposition of AB given here in this balanced equation 2AB (g)⟶ A2 (g) + B2 (g), has rate constants of 8.58 x 10-9 L/mol s
denis-greek [22]

Answer:

3.24 × 10^5 J/mol

Explanation:

The activation energy of this reaction can be calculated using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

Where; Ea = the activation energy (J/mol)

R = the ideal gas constant = 8.3145 J/Kmol

T1 and T2 = absolute temperatures (K)

k1 and k2 = the reaction rate constants at respective temperature

First, we need to convert the temperatures in °C to K

T(K) = T(°C) + 273.15

T1 = 325°C + 273.15

T1 = 598.15K

T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now find Ea

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

8 0
2 years ago
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