1. Answer;
Copper (ii) carbonate.
The name of the compound CuCO3 is copper (ii) carbonate.
Explanation;
Cu is the chemical symbol for the copper and CO3 is the chemical symbol for the carbonate group and each one of them has valency of two. Therefore, a compound CuCO3 is formed.
2. Answer;
Yes
Ca2+ reacted with Na2S to form CaS and Na+
Explanation:
Calcium ions reacts with sodium sulfide to form calcium sulfide and sodium ions.
For example; a salt of calcium, calcium carbonate reacts with sodium sulfide to form sodium carbonate and calcium sulfide.
3. Answer;
NaCl and Ag+ do not form a product
Explanation;
The reaction between sodium chloride and silver metal will not take place. This is because silver (Ag) is less reactive than sodium metal and therefore cannot displace sodium from its salt. In other words, silver metal is lower in the reactivity series as compared to sodium metal which indicates sodium metal is more reactive than silver.
4. Answer;
Formation of a white precipitate ; this indicates that silver sulfide is insoluble in water.
Explanation;
When an aqueous solution containing Ag+ ions is added to aqueous solution of sodium sulfide (Na2S), there will be formation of white precipitate. Formation of white precipitate indicates that a reaction has taken place to form a water insoluble compound. The water insoluble compound occurs as a precipitate. The white precipitate is silver sulfide (Ag2S)
2 Ag+ (aq) + Na2S(aq) ----- Ag2S (s) + 2 Na+ (aq)
Answer : The concentration of 
in the solution is, 
Explanation :
First we have to calculate the volume of aqueous solution that is water.
Density of water = 1.00 g/mL
Mass of water = 2400 g
Now we have to calculate the concentration of ammonia solution.
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Molar mass of = 17 g/mole
Now put all the given values in this formula, we get:
Therefore, the concentration of in the solution is,
Answer : The number of moles of oxygen present in a sample are 11.3 moles.
Explanation :
The given compound is, 
By the stoichiometry we can say that, 1 mole of of has 4 moles of CO.
Or we can say that, 1 mole of of has 1 mole of nickel (Ni), 4 moles of carbon (C) and 4 moles of oxygen.
That means,
Number of moles of carbon = Number of moles of oxygen
As we are given that:
Number of moles of carbon = 11.3 moles
So, number of moles of oxygen = number of moles of carbon = 11.3 moles
Therefore, the number of moles of oxygen present in a sample are 11.3 moles.
Answer:
B
Explanation:
Diamagnetism , paramagnetism and ferromagnetism are terms which are used to describe the magnetic activity of transition metals. These terms helps to know the response the metal will have when placed in a magnetic field. These activities can be discerned from the d-block electronic configuration. If the number of electrons are even, this means they all form a pair and the metal is diamagnetic. If otherwise, there is an unpaired electron which causes the paramagnetic activity of the metal in magnetic field.
To the question, options A-D are diamagnetic but configurations with d8 are the ones that form square planar complexes
