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Alexeev081 [22]
2 years ago
7

Describe the changes in properties (from metals to nonmetals or from nonmetals to metals) as we move (a) down a periodic group a

nd (b) across the periodic table from left to right.
Chemistry
1 answer:
defon2 years ago
7 0

Answer:

Explanation:

The changes in properties from metals to non-metals on a periodic table can be measured and determined by the metallicity or electropositivity of elements.

Metallicity is a measure of the tendency of atoms of an element to lose electrons.

a.

Down a periodic group, metallicity increases.

b.

Across a period from left to right electropositivity or metallicity decreases.

Metals are found in the left part of periodic table and the most reactive metal sits in the lower left corner. Non-metals are towards the right side of the table.

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In the reaction of nitrogen gas with oxygen gas to produce nitrogen oxide, what is the effect of adding more oxygen gas to the i
Alborosie
<h3>Answer:</h3>

The Equilibrium would shift to produce more NO

<h3>Explanation:</h3>

The reaction is;

N₂(g) + O₂(g) ⇆ 2NO(g)

  • When a reaction is at equilibrium then the forward reaction rate will be equivalent to the reverse reaction rate. Additionally, the concentration of the reactants and products are the same.
  • From Le Chatelier's principle, additional reactants favor the formation of more products while additional products favor the formation of more reactants.
  • For example, when more oxygen is added then more Nitrogen (II) oxide will be formed.
  • Oxygen is a reactant and when increased it favors forward reaction which leads to the formation of more NO which is the product.

3 0
2 years ago
An ice cube with a volume of 45.0ml and a density of 0.9000g/cm3 floats in a liquid with a density of 1.36g/ml. what volume of t
Grace [21]

Answer : The volume of the cube submerged in the liquid is, 29.8 mL

Explanation :

First we have to determine the mass of ice.

Formula used :

\text{Mass of ice}=\text{Density of ice}\times \text{Volume of ice}

Given:

Density of ice = 0.9000g/cm^3=0.9000g/mL

Volume of ice = 45.0 mL

\text{Mass of ice}=0.9000g/mL\times 45.0mL

\text{Mass of ice}=40.5g

The cube will float when 40.5 g of liquid is displaced.

Now we have to determine the volume of the cube is submerged in the liquid.

\text{Volume of ice}=\frac{\text{Mass of liquid}}{\text{Density of liquid}}

\text{Volume of ice}=\frac{40.5g}{1.36g/mL}

\text{Volume of ice}=29.8mL

Thus, the volume of the cube submerged in the liquid is, 29.8 mL

5 0
2 years ago
A student wants to prepare a 1.0-liter solution of a specific Molarity. The student determines that the mass of the solute needs
Mars2501 [29]
The answer is (4) Add enough solvent to 30.0 g of solute to make 1.0 L solution. The molarity is calculated using volume of the solution. When solute dissolving, the total volume will change. So the final volume of solution need to be 1.0 L.
4 0
2 years ago
A student mixed 20.00 grams of calcium nitrate, 10.00 grams of sodium nitrate, and 50.00 grams of aluminum nitrate in a 5.00 Lit
My name is Ann [436]

Answer:

M=0.213M

Explanation:

Hello,

In this case, for each nitrate-based salt, we compute the nitrate moles as shown below:

n_{NO_3^-}=20.00gCa(NO_3)_2*\frac{1molCa(NO_3)_2}{164.088 gCa(NO_3)_2} *\frac{2molNO_3^-}{1molCa(NO_3)_2} =0.244molNO_3^-

n_{NO_3^-}=10.00gNaNO_3*\frac{1molNaNO_3}{84.9947 gNaNO_3} *\frac{1molNO_3^-}{1molNaNO_3} =0.118molNO_3^-

n_{NO_3^-}=50.00gAl(NO_3)_3*\frac{1molAl(NO_3)_3}{212.996gAl(NO_3)_3} *\frac{3molNO_3^-}{1molAl(NO_3)_3} =0.704molNO_3^-

We notice calcium nitrate has two moles of nitrate ion, sodium nitrate has one and aluminium nitrate has three. Hence we add the moles to obtain the total moles nitrate ion:

n_{NO_3^-}^{Tot}=0.244+0.118+0.704=1.066molNO_3^-

Finally, we compute the molarity:

M=\frac{1.066molNO_3^-}{5.00L} \\\\M=0.213M

Regards.

6 0
2 years ago
Which of the following molecules can form hydrogen bonds?
frosja888 [35]

Hydrogen bonding is a type of intermolecular forces of attraction in which hydrogen atom is bonded to one of the most electronegative atoms. This gives a partial positive charge to hydrogen atom and a partial negative charge to the electronegative atom involved in the bonding. The electronegative atoms that can form hydrogen bonding are fluorine (F), nitrogen (N), and oxygen (O).

Therefore the correct option is,

A) NH3

3 0
2 years ago
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