Answer:
1.3 mL
Explanation:
First, get the density of the olive oil, which is 0.917 kg/mL. Then divide the mass by the density:
1.2kg/0.917kg/mL= 1.3086150491 mL. The kg cancel out, leaving us with mL.
It should have 2 significant figures, because 1.2kg has 2 and we are dividing.
The question only asks regarding the direction of the equilibrium reaction. The general expression of Kp is:
Kp = [PCl₅]/[PCl₃][Cl₂]
The higher the value of K (greater than 1), the more spontaneous the reaction (favors the product side). Otherwise, it favors the reactant side. Since Kp = 0.087 which is less than 1, the direction favors the forward reaction towards the product side.
Answer:
3.00 cm
Explanation:
The absorbance can be expressed using <em>Beer-Lambert's law</em>:
A = ε*b*c
Where ε is a constant for each compound, b is the optical path, and c is the molar concentration of the compound.
Now we <u>match the absorbance values for both solutions</u>, because we want the absorbance value to be the same for both solutions:
A = ε * 1.00 cm * 7.68x10⁻⁶M = ε * b * 2.56x10⁻⁶ M
And <u>solve for b:</u>
ε * 1.00 cm * 7.68x10⁻⁶M = ε * b * 2.56x10⁻⁶ M
1.00 cm * 7.68x10⁻⁶M = b * 2.56x10⁻⁶ M
b = 3.00 cm
The question is incomplete , complete question is:
Hydrogen, a potential future fuel, can be produced from carbon (from coal) and steam by the following reaction:

Note that the average bond energy for the breaking of a bond in CO2 is 799 kJ/mol. Use average bond energies to calculate ΔH of reaction for this reaction.
Answer:
The ΔH of the reaction is -626 kJ/mol.
Explanation:

We are given with:



ΔH = (Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)



The ΔH of the reaction is -626 kJ/mol.
Answer:
The unknown element is Sb
Explanation:
The first thing we must note is that the unknown element must be a member of group 15 in the periodic table. This is clear from the fact that the two oxides formed are X2O3 and X2O5. This implies that the unknown element X must have a valency of 3 or 5. This corresponds to our knowledge that the outermost electron configuration of group 15 elements is ns2np3. Hence, group fifteen elements can have a valency of 3 or 5.
The electronic configuration of antimony is; [Kr]4d10 5s2 5p3. This implies that the atom is paramagnetic since there are three unpaired 5p electrons. The oxides of antimony are known to be amphoteric. An ampohoteric oxide reacts with both acid and base, hence the answer.