He person lost 1224.7 grams.
The graph is needed to answer this question.
Solubility may increase or decrease with temperature depending on the properties of the solute and the solvent.
It is quite common that the solubility of the ionic compounds, like KBr, in water increases with temperature.
Use your solubility curve for the KBr and you wiil see a line that starts at a solubility a little greater than 50 grams of the salt in 100 grams of water for temperaute 0°C and increase linearly until almost 100 grams of the salt in 100 grams of water at 100°C.
So, in this case you can affirm that the solubility of KBr increases with the temperature.
Answer: the second option: the solubility increases.
Answer:
The force increases because it is part of a Newton’s third law pair of forces with the force that the star exerts on the planet.
Explanation:
Force between two objects can be expressed by an equation:
F = G • m1 • m2 / r^2,
where m1 and m2 are objects' masses, r is the distance between them, and G is a gravitational constant.
That means that greater the masses or lesser the distance, the force will be greater, and vice versa.
This force exists between any two objects, but is generally extremely weak, so it's best observed with big and large objects with great mass, such as planets and stars.
This force, whatever its magnitude may be, always works on both objects, following the third Newton's law.
So, whatever the force the stat exerts on the planet is, the planet will exert the same amount of force on the star.
Answer:

Explanation:
A solution of a weak base and its conjugate acid is a buffer.
The equation for the equilibrium is

The Henderson-Hasselbalch equation for a basic buffer is
![\text{pOH} = \text{p}K_{\text{b}} + \log\dfrac{[\text{BH}^{+}]}{\text{[B]}}](https://tex.z-dn.net/?f=%5Ctext%7BpOH%7D%20%3D%20%5Ctext%7Bp%7DK_%7B%5Ctext%7Bb%7D%7D%20%2B%20%5Clog%5Cdfrac%7B%5B%5Ctext%7BBH%7D%5E%7B%2B%7D%5D%7D%7B%5Ctext%7B%5BB%5D%7D%7D)
Data:
[B] = 0.400 mol·L⁻¹
[BH⁺] = 0.250 mol·L⁻¹
Kb = 4.4 × 10⁻⁴
Calculations:
(a) Calculate pKb
pKb = -log(4.4× 10⁻⁴) = 3.36
(b) Calculate the pH

Answer:
Part A: 5.899x10^-3 moles of Al
Part B: 1.573 g of AlBr3
Explanation:
Part A: We have to obtain the volume of the piece of aluminium; all sides of the square must be in cm. Then, use the density to obtain the mass.


0.059 is the volume of the Al udes for the reaction. Now, to oabtain the moles:

Part B: To obatin the mass of AlBr3, we need the balanced chemical equation:
2Al + 3Br2 → 2AlBr3
We assume bromine (Br2) is in excess, therefore, we calculate the aluminum bromide formed from the Al:
of Al