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Phoenix [80]
2 years ago
14

A student has a 1g sample of each of the following compounds: NaCl, KBr, and KCL Which of the following lists the samples in ord

er of increasing number of moles in the sample?
Chemistry
1 answer:
krek1111 [17]2 years ago
4 0

Given :

A student has a 1 g sample of each of the following compounds: NaCl, KBr, and KCl.

To Find :

The samples in order of increasing number of moles in the sample.

Solution :

Molecular mass of NaCl, KBr, and KCl is 58.5 g/mol , 119 g/mol and

74.5 g/mol respectively .

Moles of NaCl , n_1=\dfrac{1}{58.5}=0.017\ mol.

Moles of KBr , n_2=\dfrac{1}{119}=0.008\ mol.

Moles of KCl , n_2=\dfrac{1}{74.5}=0.013\ mol.

The order of moles in increasing order is :

KBr , KCl and NaCl .

Hence , this is the required solution .

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At 1.01 bar, how many moles of CO2 are released by raising the temperature of 1 litre of water from 20∘C to 25∘C
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Answer: 0.0007 moles of CO_2 is released when temperature is raised.

Explanation:

To calculate the number of moles, we use the ideal gas equation, which is:

PV=nRT

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V = Volume of the gas = 1L

R = Gas constant = 0.08314\text{ L bar }mol^{-1}K^{-1}

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Temperature of the gas = 20° C = (273 + 20)K = 293K

Putting values in above equation, we get:

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Putting values in above equation, we get:

1.01bar\times 1L=n_2\times 0.0814\text{ L bar }mol^{-1}K^{-1}\times 298K\\n_2=0.04076moles

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2 years ago
A certain gas is present in a 12.0 L cylinder at 4.0 atm pressure. If the pressure is increased to 8.0 atm the volume of the gas
diamong [38]
There are 3 parts in this question:
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2) To find the final Boyle's constant k_{f}
3) To verify whether gas is obeying Boyle's law or not

Given data:
The initial volume of the cylinder(in litres) = V_{i} = 12.0 L
The initial pressure(in atmospheric pressure) = P_{i} = 4.0 atm

The final pressure(in atmospheric pressure) = P_{f} = 8.0 atm
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First you need to know what Boyle's law is:
<span>Boyle's law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.
</span>
The Mathematical form of Boyle's law is:
P =  \frac{k}{V}

Where,
P = Pressure
V = Volume of the gas
k = Boyle's constant

Now let's solve aforementioned parts one by one:
1. 
The initial volume of the cylinder(in litres) = V_{i} = 12.0 L
The initial pressure(in atmospheric pressure) = P_{i} = 4.0 atm
The Boyle's constant = k_{i} = ?

According to the Boyle's law,

P_{i} = \frac{k_{i}}{V_{i}}

=> k_{i} =  P_{i}V_{i}
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2.
The final pressure(in atmospheric pressure) = P_{f} = 8.0 atm
The final volume of the cylinder(in litres) = V_{f} = 6.0 L
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According to the Boyle's law,

P_{f} = \frac{k_{f}}{V_{f}}

=> k_{f} =  P_{f}V_{f}
Plug-in the values in the above equation, you would get:
k_{f} = 8.0 * 6.0 = 48

Ans-2) k_{f} = 48

3.
In order to verify Boyle's law, the initial Boyle's constant should be EQUAL to the final Boyle's constant, meaning:

k_{i} = k_{f}

Since,
k_{i} = 48
k_{f} = 48

Therefore,
48=48.

Ans-3) Hence proved: The gas IS obeying the Boyle's law.

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