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vovikov84 [41]
2 years ago
15

Miriam notices when she goes to the beach that sometimes the water rises as high as the pier. At other times of the day, the wat

er barely covers the pillars under the pier. These differences in water level are primarily due to the gravitational influence of which of the following?
Question 2 options:

Moon

Sun

Asteroids

Comets
Chemistry
1 answer:
kondor19780726 [428]2 years ago
3 0
High tides and low tides are caused by the moon. The moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the moon and the side farthest from the moon. These bulges of water are high tides.
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Identify the equations that show ionization. Check all that apply.
tigry1 [53]

Answer: B. HCl(g)+H2O(I)—>H3O+(aq)+Cl-(aq)

D. CO2(g)+2H2O(I)—>HCO3-(aq)+H3O+(aq)

Explanation: on edge

8 0
2 years ago
Glycerol (C3H8O3, 92.1 g/mol) is a nonvolatile nonelectrolyte substance. Consider that you have an aqueous solution that contain
pychu [463]

Answer:

The vapor pressure of the solution at 25°C is 26.01 Torr

Explanation:

This is a usual excersise of colligative properties. In this case we apply the vapor pressure lowering formula:

ΔP = Xst . P°

Where ΔP is the diferrence between  Pressure of solution - Pressure of pure solvent.

And Xst  the molar fraction.

P° is Pressure of pure solvent.

So the formula will be:

Pressure Solution - P° = Xst . P°

Pressure Solution - 23.8 Tor = Xst . 23.8 Torr

Xst : Mole fraction ( Moles of solute or solvent / Total moles)

34.4 % m/m means that in 100 g of solution I have 34.4 g of solute

If I have 34.4 g of solute and the mass of 100 g in solution, I can know the mass of solvent, and finally the moles.

100 g solution - 34.4 g solute = 65.6 g (mass of solvent)

Molar mass of water : 18 g/m

Moles of water: Mass of water / Molar mass

65.6 g / 18g/m = 3.64 moles

Moles of glycerol : Mass glycerol / Molar mass glycerol

34.4 g / 92.1 g/m = 0.373 moles

Total moles: moles of glycerol + moles of water

0.373 m + 3.64 m = 4.01 m

So Xst = 0.373 m / 4.01 m → 0.093

Pressure Solution - 23.8 Tor = 0.093 . 23.8 Torr

Xst HAVE NO UNITS

Pressure Solution = (0.093 . 23.8 Torr ) + 23.8 Tor

Pressure Solution = 26.01 Torr

6 0
2 years ago
That's just the tip of the iceberg" is a popular expression you may have heard. It means that what you can see is only a small p
puteri [66]
Answer:

B 1.23 g/cc

Explanation:
For something to float on seawater, the density must be less than 1.03 g/mL. If the object sinks, the density is greater than 1.03 g/mL.

Let’s examine the answer choices. Keep in mind, the ice berg is mostly below the water level.

A. 0.88 g/cc
This is less than 1.03 g/cc, which would result in floating.

B. 1.23 g/cc
This is the best answer choice. The iceberg is mostly beneath the water, but some of it is exposed. The density is greater than 1.03 g/mL, but not so much greater that it would immediately sink.

C. 0.23 g/cc
This is less than 1.03 g/cc, which would produce floating.

D. 4.14 g/cc
This is much greater than 1.03 g/cc and the result would be sinking.
5 0
2 years ago
What mass of Na2SO4 is needed to make 2.5L of 2.0M solution? (Na=23g; S=32g; O=16g)
zaharov [31]
The molar mass of Na₂SO₄ - 
2 x Na - 2 x23 = 46
1 x S - 1 x 32 = 32 
4 x O - 4 x 16 = 64 
total = 46 + 32 + 64 = 142 g/mol
the molarity of solution - 2.0 M 
in 1 L of solution , 2.0 moles
Therefore in 2.5 L - 2 mol/L x 2.5 L = 5 mol
then the mass of Na₂SO₄ required = 142 g/mol x 5 mol = 710 g
8 0
2 years ago
Read 2 more answers
a sample of double-stranded dna contains 42% cytosine. approximately what percent of the nucleotides in this sample will be thym
Simora [160]

Answer:

8% thymine

Explanation:

7 0
1 year ago
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