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alexgriva [62]
2 years ago
6

How can chemistry help you make wiser decisions and be a better consumer?

Chemistry
1 answer:
Cloud [144]2 years ago
4 0
<span>While we take for granted that the first step towards feeling improved is getting a diagnosis and prescription. If there are choices that could make to reduce the strength of our diet is the opening of brain chemistry. It is our body be able to only make.</span>
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A teacher wants to figure out The amount of a solution that is needed for a titration experiment in a class lab! the class has 1
AnnZ [28]
The teacher needs 1500 mL for the whole class.
5 0
2 years ago
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What is the mass (in grams) of 8.45 x 1023 molecules of dextrose: C6H12O6 (Mw. 180.16 g/mol)?
Goryan [66]
<span>The mass (in grams) of 8.45 x 10^23 molecules of dextrose is 252.798g Working: Mw. dextrose is 180.16 g/mol therefore 180.16 grams dextrose = 1 mole therefore 180.16 grams dextrose= 6.022x10^23 molecules (Avogadro's number) We have 8.45 x 10^23 molecules of dextrose. Therefore, (180.16 divided by 6.022x10^23) times 8.45x10^23 gives the mass (in grams) of 8.45 x 10^23 molecules of dextrose; 252.798.</span>
4 0
2 years ago
a compound contain 8.57g of carbon and 1.43g of hydrogen. The relative formula mass is 70 calculate the empirical formula of the
yanalaym [24]

Answer:

Empirical formula: CH2

Molecular formula: C5H10

5 0
1 year ago
To burn 1 molecule of C5H12 to form CO2 and H2O (complete combustion), how many molecules of O2 are required?
viva [34]
C5H12 + 8 O2 → 5 CO2 + 6 H2O 

8 molecules of O2 are required.
5 0
2 years ago
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Dissolving NaOH(s) in water is exothermic. Two calorimetry experiments are set up. Experiment 1: 2 g of NaOH are dissolved in 10
vlada-n [284]

Answer:

a. both temperature changes will be the same

Explanation:

When sodium hydroxide (NaOH) is dissolved in water, a determined amount is released to the solution following the equation:

Q = m×C×ΔT

<em>Where Q is the heat released, m is the mass of the solution, C is the specific heat and ΔH is change in temperature.</em>

Specific heat of both solutions is the same (Because the solutions are in fact the same). Specific heat = C.

m is mass of solutions: 102g for experiment 1 and 204g for experiment 2.

And Q is the heat released: If 2g release X heat, 4g release 2X.

Thus, ΔT in the experiments is:

Experiment 1:

X / 102C = ΔT

Experiment 2:

2X / 204C = ΔT

X / 102C = ΔT

That means,

<h3>a. both temperature changes will be the same</h3>

5 0
2 years ago
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