Answer:
The partial pressure of CO2 is 712,8 in torr
Explanation:
Molar fraction = Pressure in a compound / Total Pressure
Molar fraction H20 = 21,2 / 734 = 0,0288
Sum of molar fraction in a sample = 1
1 - 0,0288 = 0,9712 (molar fraction of CO2)
Molar fraction CO2 = Pressure CO2 / Total pressure
0,9712 . 734 = Pressure CO2
712,8 =Pressure CO2
Answer : 1721.72 g/qt are in 18.2 g/cL
Explanation :
As we are given: 18.2 g/cL
Now we have to convert 18.2 g/cL to g/qt.
Conversions used are:
(1) 1 L = 100 cL
(2) 1 L = 1000 mL
(3) 1 qt = 946 qt
The conversion expression will be:


Therefore, 1721.72 g/qt are in 18.2 g/cL
<span>decomposition of SrCO3 to SrO and CO2 =change in mass
moles of CO2 =(1.850 g - 1.445 g).
</span>Mass of <span>C<span>O2</span></span><span> in mixture: 1.850-1.445 = 0.405g
</span>0.405g/44.01 g/mol <span>C<span>O2</span></span><span> = 0.0092 moles </span><span>C<span>O2</span></span><span>.
</span>ratio of <span>C<span>O2</span></span><span> to SrO in Sr</span><span>C<span>O3</span></span><span> is 1:1
</span><span> mass ratio = 1.358/1.850 = 0.7341, </span>
or 73.41% Sr<span>C<span>O3</span></span><span>.
</span>hope this helps
Answer:
Heat transferred, Q = 1542.42 J
Explanation:
Given that,
Mass of water, m = 30 grams
Initial temperature, 
Final temperature, 
We need to find the energy transferred. The energy transferred is given by :

c is specific heat of water, c = 4.18 J/g °C
So,

So, 1542.42 J of energy is transferred.