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GuDViN [60]
2 years ago
8

How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?

Chemistry
1 answer:
solong [7]2 years ago
6 0

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

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Lelu [443]
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4 0
1 year ago
A race car is driven by a professional driver at 99 . What is this speed in and ? 1 mile = 1.61 kilometers 1 hour = 60 minutes E
slavikrds [6]

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2 years ago
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liberstina [14]

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Dmitrij [34]

Answer:

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3 0
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