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Aneli [31]
2 years ago
7

Scientists tracking a flock of ducks found that, on average, the ducks flew 740 km south in 12 hours. What were the speed and ve

locity of the flock of ducks in meters per second? Show your work.
Chemistry
1 answer:
Verizon [17]2 years ago
5 0

1) 17.1 m/s

2) 17.1 m/s south

Explanation:

1)

The speed of an object is a scalar quantity indicating "how fast" is the object moving, regardless of its direction of motion.

Being a scalar quantity, it has only a magnitude, while it doesn't have a direction.

The speed of an object is given by the formula:

v=\frac{d}{t}

where:

d is the distance covered by the object, which is the total length of the path covered by the object

t is the time taken to cover the distance d

In this problem we have:

d=740 km =740,000 m is the distance covered by the ducks

t=12 h  \cdot 60 \cdot 60 =43,200 s is the time taken

Substituting, we find:

v=\frac{740,000}{43,200}=17.1 m/s

2)

The velocity of an object is a vector quantity indicating how fast the object is moving in a certain direction.

Being a vector, velocity has both a magnitude and a direction.

The magnitude of the velocity is given by:

v=\frac{d}{t}

where

d is the displacement, which is the shortest distance in a straight line between the initial position and the final position of motion

t is the time taken for the displacement d to occur

And the direction is equal to the direction of the displacement.

In this problem:

d=740 km = 740,000 m south is the displacement

t=12 h  \cdot 60 \cdot 60 =43,200 s is the time taken

Substituting, we find:

v=\frac{740,000}{43,200}=17.1 m/s south

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A mass of 5.4 grams of aluminum (al) reacts with an excess of copper (ii) chloride (cucl2) in solution, as shown below. 3cucl2 2
horrorfan [7]

Answer:

Mass of copper produced is 19.07g

Explanation:

Let's bring out the chemical equation;

3CuCl2 + 2Al → 2AlCl3 + 3Cu

3           :   2       :   2       : 3

Upon confirming that the reaction is indeed balanced, we can proceed.

The questions asks to calculate mass of Cu formed when a mass of 5.4g of Al is being used.

From the equation, what is the relationship between Al and Cu?

2 mol of Al would react to form 3 mol of Cu

Expressing this in terms of mass, we have;

mass = no. of moles * molar mass

Mass of Aluminium = 2 * 26.98 = 53.98 g

Mass of Copper = 3 * 63.546 = 190.638g

This means;

53.98 g of Al would react to form 190.638g of Cu

So how much Cu would form from 5.4 g of Al?

This leads us to;

53.98 = 190.638

5.4 = x

Upon cross multiplication, we are left with;

x = (190.638 * 5.4) / 53.98

x = 19.07 g

Mass of copper produced is 19.07g

8 0
2 years ago
Consider the following system at equilibrium where H° = -87.9 kJ, and Kc = 83.3, at 500 K. PCl3(g) + Cl2(g) PCl5(g) If the VOLUM
7nadin3 [17]

Answer:

The value of Kc C. remains the same.

The value of Qc C. is less than Kc.

The reaction must: A. run in the forward direction to reestablish equilibrium

The number of moles of Cl2 will  B. decrease.

Explanation:

Le Chatelier's Principle states that if a system in equilibrium undergoes a change in conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.

A decrease in volume causes the system to evolve in the direction in which there is less volume, that is, where the number of gaseous moles is less.

But temperature is the only variable that, in addition to influencing equilibrium, modifies the value of the constant Kc. So if the volume of the equilibrium system is suddenly decreased at constant temperature: <u><em>The value of Kc remains the same.</em></u>

<u><em> </em></u>As mentioned, if the volume of an equilibrium gas system decreases, the system moves to where there are fewer moles. In this case, being:

PCl₃(g) + Cl₂(g) ⇔ PCl₅(g)

The equilibrium in this case then shifts to the right because there is 1 mole in the term on the right, compared to the two moles on the left. So, <u><em>The reaction must: A. run in the forward direction to reestablish equilibrium</em></u>.

By decreasing the volume, and so that Kc remains constant, being:

Kc=\frac{[PCl_{5} ]}{[PCl_{3}]*[Cl_{2}  ]}=\frac{\frac{nPCl_{5} }{Volume} }{\frac{nPCl_{3}}{Volume}*\frac{nCl_{2} }{Volume}  } =\frac{nPCl_{5}}{nPCl_{3}*nCl_{2}} *Volume

 where nPCl₅, nPCl₃ and nCl₂ are the moles in equilibrium of PCl₅, PCl₃ and Cl₂

so,  the number of moles of Cl₂ should decrease.<u><em>The number of moles of Cl2 will  B. decrease.</em></u>

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system will evolve to the right, the direct reaction prevailing, to increase the concentration of products. So in this case, if the reaction moves to the right, <em><u>the value of Qc C. is less than Kc.</u></em>

3 0
2 years ago
In a group assignment, students are required to fill 10 beakers with 0.720 M CaCl2. If the molar mass of CaCl2 is 110.98 g/mol a
8_murik_8 [283]
The answer is 200 g.

If the molar mass of CaCl2 is 110.98 g/mol, this means there are 110.98 g in 1 L of 1 M solution.
Let's find how many g of CaCl2 are present in 0.720 M.
110.98 g : 1 M = x : 0.720 M
x = 110.98 g * 0.720 M : 1 M 
x = 79.90 g

So there are 79.90 g in 0.720 M. In other words, in 1 L of 0.720 M solution there will be  79.90 g.

Now, we need to prepare ten beakers with 250 mL of solutions:
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79.90 g : 1 L = x : 2.5 L
x = 79.90 g * 2.5 L : 1 L
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8 0
2 years ago
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A LIQUID HAS THE FOLLOWING PROPERTIES: ONE PHASE, COLORLESS, BOILING POINT 95 TO 97 oC. WHICH OF THE FOLLOWING BEST DESCRIBES A
ololo11 [35]
I think it is D. coarse mixture
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8 0
2 years ago
Suppose there is 0.63 g of HNO3 per 100 mL of a particular solution. What is the concentration of the HNO3 solution in moles per
Vadim26 [7]

Answer:

There are 0.09996826 moles per liter of the solution.

Explanation:

Molar mass of HNO3: 63.02

Convert grams to moles

0.63 grams/ 63.02= 0.009996826

Convert mL to L and place under moles (mol/L)

100mL=0.1 L

0.009996826/0.1= 0.09996826 mol/L

4 0
2 years ago
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