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aev [14]
2 years ago
9

Determine the relative formula mass of hexasodium difluoride using the periodic table below. A. 138 g/mol B. 176 g/mol C. 20 g/m

ol D. 42 g/mol
Chemistry
2 answers:
Irina-Kira [14]2 years ago
4 0

Answer:

B. 176 g/mol

Explanation:

chemistry ed tell

laila [671]2 years ago
3 0

Answer:

Option B. 176g/mol

Explanation:

We'll begin by writing the chemical formula for hexasodium difluoride. This is given below:

Hexasodium means 6 sodium atom

Difluoride means 2 fluorine atom.

Therefore, the formula for hexasodium difluoride is Na6F2.

The relative formula mass of a compound is obtained by simply adding the atomic masses of the elements present in the compound.

Thus, the relative formula mass of hexasodium difluoride, Na6F2 can be obtained as follow:

Molar mass of Na = 23g/mol

Molar mass of F = 19g/mol

Relative formula mass Na6F2 = (23x6) + (19x2)

= 138 + 38

= 176g/mol

Therefore, the relative formula mass of hexasodium difluoride, Na6F2 is 176g/mol

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The noble gases are inert. This means they a. exist as gases at room temperature. b. undergo many chemical reactions. c. lose an
eduard

Answer:

D

Explanation:

The noble gases are said to be inert because they undergo very few chemical reactions. They enjoy their status by having completely filled electron shells and do not have any reason whatsoever to go into chemical reactions. Most elements otherwise go into chemical reactions principally to enjoy the stability of these elements.

Noble gases can be found in the last group of the periodic table.

8 0
2 years ago
As Jesse's hybrid accelerates to pass a car on the highway, he notices that his gas mileage drops from 40 miles per gallon to 15
e-lub [12.9K]
The most likely explanation for this observation is C. his car has turned on more pistons to provide the extra energy needed to accelerate.

When cruising, hybrid cars are able to employ electrical energy to drive the car. Moreover, even if a vehicle is not a hybrid, a greater amount of fuel is consumed when one accelerates because the vehicle has to generate a force larger than the force of air resistance in order for it to accelerate. This increased demand of force reduces the vehicle's fuel economy.
7 0
2 years ago
Read 2 more answers
An atom of beryllium (m = 8.00 u) splits into two atoms of helium (m = 4.00 u) with the release of 92.2 kev of energy. if the or
galben [10]
The kinetic energy of the products is equal to the energy liberated which is 92.2 keV. But let's convert the unit keV to Joules. keV is kiloelectro volt. The conversion that we need is: 1.602×10⁻¹⁹ <span>joule = 1 eV

Kinetic energy = 92.2 keV*(1,000 eV/1 keV)*(</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules

From kinetic energy, we can calculate the velocity of each He atom:
KE = 1/2*mv²
5.76×10²³ Joules = 1/2*(4)(v²)
v = 5.367×10¹¹ m/s
4 0
2 years ago
Read 2 more answers
A mixture of carbon dioxide and an unknown gas was allowed to effuse from a container. The carbon dioxide took 1.25 times as lon
Aleks04 [339]

Answer:

CO

Explanation:

From Graham's law, time taken to diffuse is directly proportional to the molecular mass of the gases. For two different gases.

t1/t2=√m1/m2

Since gas 1 diffuse 1.25 times as slowly as gas 2 and gas 1 is CO2 with m as 44g

1.25/1=√44/m2

Therefore m2=28g CO

7 0
2 years ago
What mass (g) of barium iodide is contained in 188 ml of a barium iodide solution that has an iodide ion concentration of 0.532m
Katarina [22]

Answer:

What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?

A) 19.6

B) 39.1

C) 19,600

D) 39,100

E) 276

The correct answer to the question is

B) 39.1  grams

Explanation:

To solve the question

The molarity ratio is given by

188 ml of 0.532 M solution of iodide.

Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles

To find the mass, we note that the Number of moles = \frac{Mass}{Molar Mass} from which we have

Mass = Number of moles × molar mass

Where the molar mass of Barium Iodide = 391.136 g/mol

= 0.100016 moles ×391.136 g/mol = 39.12 g

8 0
2 years ago
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