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Marrrta [24]
2 years ago
8

How is a yeast cell different from an onion skin cell? Yeast can reproduce by budding. Onion cells do not reproduce by budding.

Yeast lacks a membrane-bound nucleus. The onion skin cell has one. Yeast has chloroplasts. The onion skin cell doesn't have chloroplasts. Yeast lacks a cell membrane. An onion skin cell has a cell membrane.

Chemistry
2 answers:
Jlenok [28]2 years ago
7 0

Answer:

Yeast cell is different from an onion skin cell in that Yeast can reproduce by budding while onion skin cells do not reproduce by budding.

Explanation:

  • Reproduction is one of the characteristics of living organisms. All living organisms undertake reproduction to give rise to new organisms.
  • There are two major types of reproduction namely asexual and sexual reproduction.
  • Asexual reproduction is a form of reproduction that does not involve the fusion of gametes among organisms. Examples of asexual reproduction are budding in yeast and vegetative propagation in plants such as onions.
  • Sexual reproduction, on the other hand, involves the fusion of gametes from male and female organisms which results in the formation of an embryo that develops to the fetus which becomes the offspring.
  • Therefore, we could say that yeast cells reproduce asexually through budding while onions reproduce asexually through vegetative propagation.
Natali [406]2 years ago
4 0

Answer:

The answer is:

Yeast can reproduce by budding. Onion cells do not reproduce by budding.

I had the same quiz.

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Making the simplistic assumption that the dissolved NaCl(s) does not affect the volume of the solvent water, determine the const
shtirl [24]

Answer:

  • m = 1,000/58.5
  • b = - 1,000 / 58.5

1) Variables

  • molarity: M
  • density of the solution: d
  • moles of NaCl: n₁
  • mass of NaCl: m₁
  • molar mass of NaCl: MM₁
  • total volume in liters: Vt
  • Volume of water in mililiters: V₂
  • mass of water: m₂

2) Density of the solution: mass in grams / volume in mililiters

  • d = [m₁ + m₂] / (1000Vt)

3) Mass of NaCl: m₁

    Number of moles = mass in grams / molar mass

    ⇒ mass in grams = number of moles × molar mass

        m₁ = n₁ × MM₁


4) Number of moles of NaCl: n₁

   Molarity = number of moles / Volume of solution in liters

   M = n₁ / Vt

   ⇒ n₁ = M × Vt


5) Substitue in the equation of m₁:

   m₁ = M × Vt × MM₁


6) Substitute in the equation of density:

    d = [M × Vt × MM₁ + m₂] / (1000Vt)


7) Simplify and solve for M

  • d = M × Vt × MM₁ / (1000Vt) + m₂/ (1000Vt)
  • d = M × MM₁ / (1000) + m₂/ (1000Vt)

Making the simplistic assumption that the dissolved NaCl(s) does not affect the volume of the solvent water means 1000Vt = V₂  

  • d = M × MM₁ / (1000) + m₂/ V₂

        m₂/ V₂ is the density of water: 1.00 g/mL

  • d = M × MM₁ / (1000) + 1.00 g/mL
  • M × MM₁ / (1000) = d - 1.00 g/mL
  • M = [1,000/MM₁] d - 1,000/ MM₁

8) Substituting MM₁ = 58.5 g/mol

  • M = [1,000/58.5] d - [1,000/ 58.5]

Comparing with the equation Molarity = m×density + b, you obtain:

  • m = 1,000/58.5
  • b = - 1,000/58.5
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