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nirvana33 [79]
2 years ago
13

A diver is going through ocean search-and-rescue training. The graph shows the relationship between her depth and the time in se

conds since starting her dive.
A. What details can you determine about the dive from the coordinates of the point (5, −8)?
Chemistry
1 answer:
Bas_tet [7]2 years ago
4 0

Answer:

The answer is below

Explanation:

The graph is attached. The time in seconds (s) is plotted on the x axis and the depth in feet (ft) on the y axis.A positive depth is used to represent above the water and a negative depth means below the water.

From the graph, the point (5, -8)  is the maximum depth in which the diver has traveled. This means that at 5 seconds, the diver was 8 feet below the water. After 5 seconds, the diver start to swim ul\p

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How are oxygen and<br> water molecules different<br> from argon and neon<br> molecules?
Ghella [55]

Answer:Argon is an element on the periodic table. It is a member of the noble gasses, meaning that it is a monoatomic pure gas. In other words, argon gas particles are simply pure single atoms of argon. ... Finally, water is a polyatomic molecule H2O composed of two atoms of hydrogen and one atom of oxygen.

Explanation:

4 0
2 years ago
During a laboratory experiment, 46.54 grams of Al2O3 was formed when O2 reacted with aluminum metal at 300.0 K and 1.2 atm. What
cupoosta [38]

Answer:

14.04 L.

Explanation:

  • The balanced reaction to form Al₂O₃ is:

<em>4Al + 3O₂ → 2Al₂O₃,</em>

4.0 moles of Al react with 3.0 moles O₂ to produce 2.0 moles Al₂O₃.

  • Firstly, we need to calculate the no. of moles in (46.54 grams) of Al₂O₃:

<em>n = mass/molar mass </em>= (46.54 g) / (101.96 g/mol) = <em>0.4565 mol.</em>

<em></em>

<u><em>Using cross multiplication:</em></u>

3.0 moles of O₂ produce → 2.0 mole Al₂O₃, from the stichiometry.

??? moles of O₂ produce → 0.4565 mole Al₂O₃.

<em>∴ The no. of moles of O₂ needed to produce 0.4565 mol (46.54 grams) of Al₂O₃</em> = (3.0 mol)(0.4565 mol)/(2.0 mol) = <em>0.6847 mol.</em>

  • To calculate the volume of O₂ needed to produce 0.4565 mol (46.54 grams) of Al₂O₃, we can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm (P = 1.2 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 0.6847 mol).

R is the general gas constant (R = 0.082 L/atm/mol.K),

T is the temperature of the gas in K (T = 300.0 K).

<em>∴ V = nRT/P</em> = (0.6847 mol)(0.082 L/atm/mol.K)(300.0 K)/(1.2 atm) =<em> 14.04 L.</em>

3 0
2 years ago
Read 2 more answers
What is the iupac name of this structure?
alexgriva [62]

Answer:

3–ethyl–4–methylhexane.

Explanation:

To name the above compound, do the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Give the substituent the lowest possible count.

5. Combine the above to name the compound.

Now, we shall name the compound given in the question above as follow:

1. The compound contains only single bond. Therefore, the compound belong to the alkane family.

2. The longest continuous carbon chain is 6 i.e hexane.

3. The substituent group attached are:

i. Methyl, CH3.

ii. Ethyl, CH2CH3.

4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,

Ethyl is located at carbon 3.

Methy is located at carbon 4.

5. Therefore, the name of the compound is:

3–ethyl–4–methylhexane.

5 0
2 years ago
Which sentence correctly describes an aspect of the Antarctic treaty system
kirza4 [7]
The answer is C. It bans the exploitation of mineral resources 
8 0
2 years ago
Read 2 more answers
The weight percent of concentrated HClO4(aq) is 70.5% and its density is 1.67 g/mL. What is the molarity of concentrated HClO4
ollegr [7]

Answer:

[HClO₄] = 11.7M

Explanation:

First of all we need to know, that a weight percent represents, the mass of solute in 100 g of solution.

Let's convert the mass to moles → 70.5 g . 1mol/100.45 g = 0.702 moles

Now we can apply the density to calculate the volume.

Density always refers to solution → Solution density = Solution mass / Solution volume

1.67 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.67 g/mL → 59.8 mL

To determine molarity (mol/L) we must convert the mL to L

59.8 mL . 1L/1000mL = 0.0598 L

Molarity → Moles of solute in 1L of solution → 0.702 mol / 0.0598 L = 11.7M

8 0
2 years ago
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