Question

The heat capacity of solid iron is 0.447 J/gËC. If the same quantity of energy were transferred to a 450 g chunk of iron at 20ËC, what would be the final temperature?

Answer 1

Answer:

$T_f=343.14^{\circ} C$

Explanation:

Given that,

The heat capacity of solid iron is 0.447 J/g°C.

Mass, m = 450 g

Initial temperature, $T_i=20^{\circ} C$

Let the heat transferred, Q = 65 kJ

We need to find the final temperature. The heat transferred is given by :

$Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q+mcT_i=mcT_f\\\\T_f=\dfrac{Q+mcT_i}{mc}\\\\=\dfrac{65000+450\times 0.447\times 20}{450\times 0.447}\\\\=343.14^{\circ} C$

So, the final temperature is $343.14^{\circ} C$.