Question

The frequency of a photon that has an energy of 3.7 × 10-18 j is ________ s-1.

Answer 1

As we know there is direct relation between Enerfy and Frequence, So,

                                              E  ∞  υ

To remove proportionality sign,

                                              E  =  h  υ     ----- (1)
Where,
            E  =  Energy

            h  =  Planck's Constant  =  6.626 × 10⁻³⁴ Kg m² s⁻¹

            υ  =  Frequency

Solving eq. 1 for υ,

                                              υ  =  E / h
Putting Values,

                               υ  =  3.7 × 10⁻¹⁸ Kg.m².s⁻² / 6.626 × 10⁻³⁴ Kg m² s⁻¹

                               υ  =  5.58 × 10¹⁵ s⁻¹

Answer 2

Answer: The frequency of the photon is $5.58\times 10^{15}s^{-1}$

Explanation:

The relationship between energy and frequency is given by Planck's equation, which is:

$E=h\nu$

where,

h = Planck's constant = $6.626\times 10^{-32}Js$

E = energy of the photon = $3.7\times 10^{-18}J$

$\nu$ = frequency of photon = ?

Putting values in above equation, we get:

$3.7\times 10^{-18}J=6.626\times 10^{-34}Js\times \nu\\\\\nu=\frac{3.7\times 10^{-18}J}{6.626\times 10^{-34}Js}=5.58\times 10^{15}s^{-1}$

Hence, the frequency of the photon is $5.58\times 10^{15}s^{-1}$