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nata0808 [166]
1 year ago
9

Determine the mass of oxygen in a 7.20 g sample of Al2(SO4)3.

Chemistry
2 answers:
Mekhanik [1.2K]1 year ago
5 0

Given:

7.20 g sample of Al2(SO4)3

Required:

Mass of oxygen

Solution:

                Since you are not given a chemical reaction, just base your solution to the chemical formula given.

Molar mass of Al2(SO4)3 = 342.15 g/mol

7.20 g Al2(SO4)3 (1 mol/342.15g)(3mol O/2 mol Al)(1 mol O2/1/2 mol O2)(32g O2/1mol O2) = 4.04 g O2

Anarel [89]1 year ago
3 0

7.20 g of a sample of Al2(SO4)3 contains 4.04 g of oxygen.

<h2>Further Explanation</h2><h3>A compound  </h3>
  • A compound is a substances that contains two or more different atoms that are bonded together. When the atoms are similar the substance is known as a molecule, therefore not all molecules are compounds.
<h3>Molar mass </h3>
  • Molar mass is the mass of one mole of a compound or a substance. The molar mass of a compound is the mass that is equivalent to the sum of relative atomic masses of the atoms of elements making up the compound.
<h3>Mass percent composition of a compound </h3>
  • Mass percent composition of a compound is calculated by dividing the mass of element in one mole of the compound by the molar mass of the compound and multiplying by 100%.

In this case we are require to calculate the mass of Oxygen in 7.2 g of Al2(SO4)3

  • Therefore; the molar mass of Al2(SO4)3 will be; 342.15 g/mol  
  • Al2(SO4)3 is made up of two Al atoms, three sulfur atoms, and 12 oxygen atoms.

Therefore;

1 mole of Al2(SO4)3 contains a mass of 192 g of Oxygen  

Thus; A sample of 7.20 g Al2(SO4)3 will contain;

= ((7.2 g Al2(SO4)3x(192 g O))/ 342.15 g/mol Al2(SO4)3

= 4.04 g Oxygen  

Keywords: Molar mass, compound  

<h3>Learn more about: </h3>
  • Compounds: brainly.com/question/1194814
  • Atoms: brainly.com/question/12505687
  • Percentage composition by mass in compounds: brainly.com/question/9118852

Level: High school  

Subject: Chemistry  

Topic: Compounds and mixtures  

Sub-topic: Composition of compounds  

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Afina-wow [57]

Answer:

Y=75.6\%

Explanation:

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In this case, since no information about the reacting hydrogen is given, we can assume that it completely react with the 28.0 g of acetylene to yield ethane. In such a way, via the 1:1 mole ratio between acetylene (molar mass = 26 g/mol) and ethane (molar mass = 30 g/mol), we compute the yielded grams, or the theoretical yield of ethane as shown below:

m_{C_2H_6}^{theoretical}=28.0gC_2H_2*\frac{1molC_2H_2}{26gC_2H_2}*\frac{1molC_2H_6}{1molC_2H_2}  *\frac{30gC_2H_6}{1molC_2H_6}\\ \\m_{C_2H_6}^{theoretical}=32.3gC_2H_6

Hence, by knowing that the percent yield is computed via the actual yield (24.5 g) over the theoretical yield, we obtain:

Y=\frac{24.5g}{32.3g}*100\%\\ \\Y=75.6\%

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3 0
2 years ago
The atomic radius of magnesium is 150 pm. The atomic radius of strontium is 200 pm. What is the atomic radius of calcium
Anon25 [30]

Answer:

The atomic radius of calcium is approximately 175

Explanation:

Given that the atomic radius of magnesium = 150 pm

The atomic radius of strontium = 200 pm

Therefore, given that calcium comes in between magnesium and strontium in group 2 of the periodic table, the atomic radius should be half way between the length of the atomic radius of magnesium and strontium, given that the atomic radius is not a fixed quantity

Therefore;

The atomic radius of calcium is approximately given as follows;

The approximate atomic radius (200 + 150)/2 = 175 pm.

7 0
2 years ago
. A saturated solution of Ag2SO4 at 25°C contains 0.032 M Ag+ ions. From this information, estimate the ΔG°rxn for the dissoluti
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Answer:

20 kJ/mol

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From ∆G°= -RTlnK

But

Ag2SO4(s)<----------->2Ag+(aq) + SO4^2-(aq)

Ksp= [2Ag+]^2 [SO4^2-]

But Ag+ = 0.032M

Ksp= (2×0.032)^2 (0.032)

Ksp= 1.31072×10^-4

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∆G°= -(8.314× 298×(-8.93976))= 20KJmol-1( to the nearest KJ)

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2 years ago
A bag of fertilizer is labeled 10-20-20. What is the actual percentage of phosphorus in the fertilizer?
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Answer:

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They are often designated NPK fertilizers.

  Now we know that the numbers 10-20-20 depicts the nitrogen-phosphorus and potassium content of the fertilizer.

From the designation,

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8 0
2 years ago
The number of atoms in 98.3g mercury
Virty [35]
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Number of atoms = moles x 6.02 x 10^23
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Hope this helps!
                          


6 0
2 years ago
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