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2 years ago

How many liters of SO2 will be produced from 26.9L O2?

Chemistry

1 answer:

Alexeev081 [22]2 years ago

5 0

Answer:

26.9 L SO₂

Explanation:

Step 1: Write the balanced equation

S(s) + O₂(g) = SO₂(g)

Step 2: Establish the appropriate volume ratio

For gases at the same conditions, the volume ratio is equal to the molar ratio. The volume ratio of O₂(g) to SO₂(g) is 1:1.

Step 3: Calculate the liters of SO₂ produced from 26.9 L of O₂

We will use the previously established volume ratio.

26.9 L O₂ × 1 L SO₂/1 L O₂ = 26.9 L SO₂

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A cylinder contains 4.0 g of nitrogen gas. A piston compresses the gas to half its initial volume. Afterward, by what factor has

notka56 [123]

Answer:

The mass density will be doubled

Explanation:

Density is given by dividing the mass of a substance by its volume.
An increase in mass causes an increase in density and vice versa, while a decrease in volume causes an increase in density and volume.
Therefore, when the volume is halved, then the density will be doubled if the mass is kept constant.
This has no effect on the number of moles as the mass is constant.

8 0

2 years ago

What mass of powdered drink mix is needed to make a 0.5 M solution of 100 mL?

Maru [420]

Answer:

There is 17,114825 g of powdered drink mix needed

Explanation:

<u>Step 1 :</u> Calculate moles

As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L

Since the volume is 100mL, we have to convert the concentration,

⇒0.5 / 1 = x /0.1 ⇒ 0.5* 0.1 = x = 0.05 M

This means there is 0.05 mol per 100mL

<u>Step 2 </u>: calculate mass of the powdered drink

here we use the formula n (mole) = m(mass) / M (Molar mass)

⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.

0.05 mol = mass / 342.2965 g/mol

To find the mass, we isolate it ⇒0.05 mol * 342.2965 g/mol = 17,114825g

There is 17,114825 g of powdered drink mix needed

3 0

2 years ago

Read 2 more answers

For the reaction: MgF2(s) ⇌ Mg2+(aq) + 2F- (aq), Ksp= 6.4 × 10-9, the addition of 0.10 M NaF to the solution cause what effect o

galina1969 [7]

Answer:

Shifts the equilibrium to the left. reduces solubility.

Explanation:

MgF2(s) ↔ Mg2+(aq) + 2F-(aq)

S S 2S

∴ Ksp = 6.4 E-9 = [ Mg2+ ] * [ F- ]² = S * (2S)²

⇒ 4S² * S = 6.4 E-9

⇒ 4S³ = 6.4 E-9

⇒ S³ = 1.6 E-9

⇒ S = 1.1696 E-3 M

NaF(s) → Na+(aq) + F-(aq)

0.10M 0.10M 0.10M

MgF2(s) ↔ Mg2+(aq) + 2F-(aq)

S' S' 2S' + 0.10

⇒ Ksp = 6.4 E-9 = (S')*(2S' + 0.10)²

If we compare the concentration (0.10 M) of the ion with Ksp ( 6.4 E-9 ); thne we can neglect S' as adding:

⇒ 6.4 E-9 = (S')*(0.10)² = 0.01S'

⇒ S' = 6.4 E-7 M

∴ % S' = ( 6.4 E-7 / 0.1 )*100 = 6.4 E-4% <<< 5%, we can make the assumption

We can observe that S >> S' ( 1.1696 E-3 M >> 6.4 E-7 M ), which shows that the solubility is reduced by the efect of the common ion from the salt, which causes the equilibrium to shift to the left, precipitating part of MgF2(s).

8 0

2 years ago

. Divide 94.20 g by 3.167 22 mL.

jeka94

94.20 g/3.16722 mL = 29.74 g/mL

The ratio of mass to volume is equal to the substance's density. Thus, 29.74 g/mL is the density of whatever substance it may be. Density does not change for incompressible matter like solid and some liquids. Although, it may be temperature dependent.

7 0

2 years ago

Read 2 more answers

The nucleoside adenosine exists in a protonated form with a pKa of 3.8. The percentage of the protonated form at pH 4.8 is close

Natasha_Volkova [10]

Answer:

Ok:

Explanation:

So, you can use the Henderson-Hasselbalch equation for this:

pH = pKa + log( $A^-/HA$ ) where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.

We can solve that

1 = log( $A^-/HA\\$ ) and so 10 = $A^-/HA$ or 10HA = A-. For every 1 protonated form of adenosine (HA), there are 10 A-. So, the percent in the protonated form will be 1(1+10) or 1/11 which is close to 9 percent.

6 0

2 years ago