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Marina CMI [18]
1 year ago
10

How many liters of SO2 will be produced from 26.9L O2?

Chemistry
1 answer:
Alexeev081 [22]1 year ago
5 0

Answer:

26.9 L SO₂

Explanation:

Step 1: Write the balanced equation

S(s) + O₂(g) = SO₂(g)

Step 2: Establish the appropriate volume ratio

For gases at the same conditions, the volume ratio is equal to the molar ratio. The volume ratio of O₂(g) to SO₂(g) is 1:1.

Step 3: Calculate the liters of SO₂ produced from 26.9 L of O₂

We will use the previously established volume ratio.

26.9 L O₂ × 1 L SO₂/1 L O₂ = 26.9 L SO₂

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Which MOST CLOSELY identifies a theme in this passage?
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Answer:

B)

Explanation:

It is the theme of the passage.

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If an electronic balance reports an object weighing 35.9920g what will be displayed when
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2.0000 g

Explanation:

It will show the number out to the 4th decimal place.  Exactly 2 g will be displayed as 2.0000 g.

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2 years ago
175 mL of Cl2 gas is held in a flexible vessel at
Gnoma [55]

Answer:

V₂ = 15.6 L

Explanation:

Given data:

Initial volume = 175 mL  (0.175 L)

Initial pressure = 1 atm

Initial temperature = 273 K

Final temperature = -5°C (-5+273 = 268 K)

Final volume = ?

Final pressure = 1.16 kpa (1.16/101=0.011 atm)

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 0.175 L × 268 K / 273 K × 0.011 atm

V₂ = 46.9 L / 3.003

V₂ = 15.6 L

7 0
2 years ago
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Which type of bond will chromium atoms likely to form with other chromium atoms
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The answer to this question is A
8 0
2 years ago
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7.00g of Compound X with molecular formula C5H10 are burned in a constant-pressure calorimeter containing 35.00kg of water at 25
horsena [70]

Answer:

The standard heat of formation of Compound X at 25°C is -3095.75 kJ/mol.

Explanation:

Mass of compound X = 7.00 g

Moles of compound X = \frac{7.00 g}{70 g/mol}=0.100 mol

Mass of water in calorimeter ,m= 35.00 kg = 35000 g

Change in temperature of the water in calorimeter = ΔT

ΔT = 2.113°C

Specific heat capacity of water ,c= 4.186 J/g °C

Q =  m × c × ΔT

Q=35000 g\times 4.186 J/g ^oC\times 2.113^oC=309,575.6 J=309.575 kJ

Heat gained by 35 kg of water is equal to the heat released on burning of 0.100 moles of compound X.

Heat of formation of Compound X at 25°C:

\frac{-Q}{\text{moles of compound X}}=\frac{-309.575 }{0.100 mol}

= -3095.75 kJ/mol

6 0
2 years ago
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