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nydimaria [60]
1 year ago
13

What is the mass of 2.25 mol of the element Iron (Fe)?

Chemistry
2 answers:
aliina [53]1 year ago
4 0

Answer:

d

Explanation:

Dimas [21]1 year ago
4 0
The answer is D I hope this help
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Which is an example of how society affects science?
Evgesh-ka [11]

Answer: Laws have been passed banning the production of a living copy of a person.

i just took the test so i know the answer is correct.

6 0
2 years ago
Read 2 more answers
500ml of a buffer solution contains 0.050 mol nahso3 and 0.031
nydimaria [60]

Answer:

The answers are explained below

Explanation:

a)

Given: concentration of salt/base = 0.031

concentration of acid = 0.050

we have

PH = PK a + log[salt]/[acid] = 1.8 + log(0.031/0.050) = 1.59

b)

we have HSO₃⁻ + OH⁻ ------> SO₃²⁻ + H₂O

Moles i............0.05...................0.01.................0.031.....................0

Moles r...........-0.01.................-0.01................0.01........................0.01

moles f...........0.04....................0....................0.041.....................0.01

c)

we will use the first equation but substituting concentration of base as 0.031 + 10ml = 0.031 + 0.010 = 0.041

Hence, we have

PH = PK a + log[salt]/[acid] = 1.8 + log(0.041/0.050) = 1.71

d)

pOH = -log (0.01/0.510) = 1.71

pH = 14 - 1.71 = 12.29

e)

Because the buffer solution (NaHSO3-Na2SO3) can regulate pH changes. when a buffer is added to water, the first change that occurs is that the water pH becomes constant. Thus, acids or bases (alkali = bases) Additional may not have any effect on the water, as this always will stabilize immediately.

4 0
2 years ago
A compound composed of 3.3% H, 19.3% C, and 77.4% O3.3% H, 19.3% C, and 77.4% O has a molar mass of approximately 60 g/mol.. Wha
11111nata11111 [884]

Answer:

Molecular formula of the compound = H₂CO₃

Explanation:

First, the empirical formula of the compound is determined

Percentage by mass of each element is given as shown below:

H = 3.3% ; C = 19.9%; O = 77.4%

Mole ratio of the elements= percentage mass/ molar mass

H = 3.3/ 1 = 3.3

C = 19.3/12 = 1.6

O = 77.4/16 = 4.8

whole number ratio is obtained by dividing through with the smallest ratio

H = 3.3/1.6; C = 1.6/1.6; O = 4.8/1.6

H : C : O = 2 : 1 : 3

Empirical formula = H₂CO₃

Molecular formula/mass = n(empirical formula/mass)

60 = n(2*1 + 12*1 + 16*3)

60 = n(62)

n = 60/62 = 0.96

n is approximately = 1

Therefore, molecular formula of the compound = (H₂CO₃) * 1

Molecular formula of the compound = H₂CO₃

6 0
1 year ago
If the patient has to be administered a dosage of 2 tablets every 8 hours for 7 days, what is the number of tablets required for
Lilit [14]
If the patient has to take 2 tablets every 8 hours for 7 days.
 24/8=3     3*2=6
this means that he patient will have to take 6 tablets every day. 
6*7=42   And the patient must take 42 tablets in all 7 days
Hope this helps! :)
6 0
1 year ago
Anne prepares a solution of copper nitrate with a concentration of 30 g/dm³. What mass of copper nitrate did she add to 100cm³ o
strojnjashka [21]

Answer:

3 g

Explanation:

Concentration of copper nitrate needed = 30 g/dm³

Volume of water = 100 cm³ = 0·1 dm³

( ∵ 1 dm³ = 1000 cm³)

Let the mass of copper nitrate that should be added to 100 cm³ water be m g

m ÷ 0·1 = 30

∴ m = 3 g

∴ Mass of copper nitrate that should be added to 100 cm³ of water = 3 g

7 0
1 year ago
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