Answer:
.997 atm
Explanation:
1. Find the combined gas law formula...
(P1V1/T1 = P2V2/T2)
2. Find our numbers...
P1= .982 atm
P2= ? (trying to find)
V1= 2 L
V2= 1.8 L
T1= 22 C = 295 K
T2= -3 C = 270 K
- Note: always use Kelvin. To find Kelving add 273 to ___C.
3. Rearrange formula to fit problem...
(P2=P1V1T2/V2T1)
4. Fill in our values...
P2= .982 atm x 2 L x 270 K / 1.8 L x 295 K
5. Do the math and your answer should be...
.997 atm
- If you need more help or still do not understand please let me know and I would be glad to help!
Answer:
It is neutral (NR)
Explanation:
Salts are formed when the ionizable hydrogens in an acid is replaced by metallic or ammonium ions from bases. The reaction is known as a neutralization reaction.
The nature of a salt formed from this reaction depends on the nature of the reacting acid and base.
If the reaction is between a strong acid and strong base, the salt produced is a neutral salt.
If the reaction occurs between a strong acid and a weak base, the salt produced is acidic.
If the reaction occurs between a strong base and a weak acid, the salt produced is a basic salt.
Considering the salt above, LiNO3.
On hydrolysis, addition of water, the following products are obtained:
LiNO3 + H2O ----> LiOH + HNO3
The products obtained, LiOH and HNO3 are a strong base and a strong acid respectively. Therefore, the salt, LiNO3, is a neutral salt.
Answer:
d. The limiting reactant is Br2, and 0.13 mol Al should remain unreacted.
Explanation:
From the reaction, 2Al(s) + 3Br2(l) → 2AlBr3(s)
2 moles of Al combines with 3 moles of Br to form 2 moles of AlBr3
Hence 1 mole of Br combines with 2/3 moles of Al
or 0.4 moles of Br combines with 2/3×0.4 moles of Al or 0.267 Moles of Al leaving
0.4 - 0.267 = 0.133 moles of Al remaining unreacted
Answer:
The answer is A (number 1)