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Marysya12 [62]
2 years ago
13

s PCl_3 + Cl_2" alt="PCl_5 \rightleftarrows PCl_3 + Cl_2" align="absmiddle" class="latex-formula">PCl₅ (g) decomposes into PCl₃ (g) and Cl₂ (g) according to the equation above. A pure sample of PCl₅ (g) is placed in a rigid, evacuated 1.00 L container. The initial pressure of the PCl₅ (g) is 1.00 atm. The temperature is held constant until the PCl₅ (g) reaches equilibrium with its decomposition products.If the decomposition reaction were to go to completion, the total pressure in the container will be:(A) 1.4 atm(B) 2.0 atm(C) 2.8 atm(D) 3.0 atm
Chemistry
1 answer:
Butoxors [25]2 years ago
3 0

<u>Answer:</u> The total pressure of the container will be 2.00 atm

<u>Explanation:</u>

We are given:

Initial moles of phosphorus pentachloride = 1.00 atm

For the given chemical reaction:

PCl_5\rightleftharpoons PCl_3+Cl_2

By Stoichiometry of the reaction:

1 mole of PCl_5 produces 1 mole of PCl_3 and 1 mole of chlorine gas

So, 1.00 atm of PCl_5 will also produce 1.00 atm of PCl_3 and 1.00 atm of chlorine gas when the reaction goes to completion.

Total pressure of the container when the reaction goes to completion  = 1.00 + 1.00 = 2.00 atm

Hence, the total pressure of the container will be 2.00 atm

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Answer:-A. It is less than 890 kJ/mol because the amount of energy required to break bonds is less than the amount of energy released in forming bonds.

Explanation: Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and \Delta H for the reaction comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

In the formation of new bonds more energy is released than is required to break the existing bonds, heat is released.

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8 0
1 year ago
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Answer is: a lower freezing point has solution of K₂SO₄.

Change in freezing point from pure solvent to solution: ΔT =i · Kf · b.<span>
Kf - molal freezing-point depression constant for water is 1.86°C/m.
b -  molality, moles of solute per kilogram of solvent.
i - </span>Van't Hoff factor.<span>
b(K</span>₂SO₄<span>) = 0.35 m.
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2.  An unsaturated hydrocarbon molecule contains at least one double bond.

Explanation:

Hello,

In this case, hydrocarbons are defined as the simplest organic compounds containing both carbon and hydrogen only, for that reason we can immediately discard the third statement as ethylenediamine is classified as an amine (organic chain containing NH groups).

Next, as saturated hydrocarbons only show single carbon-to-carbon bonds and carbon-to-hydrogen bonds, they may be cyclic (ring-like-shaped) or acyclic (not forming rings), so first statement is true

Finally, since we can find saturated hydrocarbons which have single carbon-to-carbon and carbon-to-hydrogen bonds only and unsaturated hydrocarbons which could have double or triple bonds between carbons and carbon-to-hydrogen bonds, the presence of at least one double bond makes the hydrocarbon unsaturated.

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