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blsea [12.9K]
2 years ago
11

Carbon absorbs energy at a wavelength of 150. nm. The total amount of energy emitted by a carbon sample is 1.98 3 105 J. Calcula

te the number of carbon atoms present in the sample, assuming that each atom emits one photon.
Chemistry
1 answer:
Rufina [12.5K]2 years ago
7 0

Answer:

Explanation:

The first thing we need to do is to convert the wavelength to meters. We should remember that 1 meter is 1x10^9 nm so:

∧ = 150 nm / 1x10^9 nm = 1.5x10^-7 m

The formula for Energy in this case is:

E = hc/∧

We already know that c is the speed of light, which is 3x10^8 m/s and h is the planck constant which is 6.63x10^-34  J.s

Replacing data in the above formula:

E = 6.63x10^-34 * 3x10^8 / 1.5x10^-7 = 1.33x10^-18 J per photon.

Now finally to calculate the carbon atoms present in the sample, let's calculate the number of photons:

n° of photons = 1.98x10^5 / 1.33x10^-18

n° of photons = 1.49x10^23 photons

The exercise states that one atom emits on photon, so we can assume that this final result would be the number of carbon atoms present in the sample.

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When the element in group 1 are considered in order from top to bottom, each successive Elmer at standard pressure has a lower melting point and a lower boiling point.
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1. Which class of compounds contains at least one element from Group 17 of the Periodic Table ? A) aldehyde B ) amine C) ester D
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Halide

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Pesticide concentrations in the Rhine River between Germany and France between 1969 and 1975 averaged 0.55 mg/L of hexachloroben
sertanlavr [38]

Answer:

1.93×10⁻³ mmoles/L of C₆Cl₆; 1.58×10⁻⁴ mmoles/L of C₁₂H₈Cl₆O; 3.51×10⁻³ mmoles/L of C₆H₆Cl₆

Explanation:

We have to find out the molar mass of each pesticide to calculate the moles, and then the milimoles

C₆Cl₆ → 12. 6 + 35.45 .6 = 284.7 g/m

C₁₂H₈Cl₆O →  12 . 12 + 8.1 + 35.45 .6 + 16 = 380.7 g/m

C₆H₆Cl₆ → 12.6 + 6.1 + 35.45 .6 = 290,7 g/m

Let's convert mg to g (/1000)

0.55 mg / 1000 = 5.5×10⁻⁴ g

0.060 mg / 1000 = 6×10⁻⁵ g

1.02 mg / 1000 = 1.02×10⁻³ g

Now we can know the moles (mass / molar mass)

5.5×10⁻⁴ g / 284.7 g/m = 1.93×10⁻⁶ moles of C₆Cl₆

6×10⁻⁵ g / 380.7 g/m = 1.58×10⁻⁷ moles of C₁₂H₈Cl₆O

1.02×10⁻³ g / 290,7 g/m = 3.51×10⁻⁶ moles of C₆H₆Cl₆

Milimoles = Mol . 1000

1.93×10⁻⁶ . 1000 = 1.93×10⁻³ mmoles of C₆Cl₆

1.58×10⁻⁷ . 1000 = 1.58×10⁻⁴ mmoles of C₁₂H₈Cl₆O

3.51×10⁻⁶ . 1000 = 3.51×10⁻³ mmoles of C₆H₆Cl₆

6 0
2 years ago
Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0
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Answer:

The freezing point will be 2.9^{0}C

Explanation:

The depression in freezing point is a colligative property.

It is related to molality as:

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Where

Kf= 20\frac{^{0}C}{m}

the molality is calculated as:

molality=\frac{moles_{solute}}{mass_{solvent}}

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molarity=\frac{0.0045}{0.025}=0.18m

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The new freezing point = 6.5^{0}C-3.6^{0}C=2.9^{0}C

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