The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition.
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
(800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
V2 = 34.1 mL
Answer: As mass is constant during free-weight resistance training, a greater impulse will result in a greater velocity. Therefore, as generation of force greater than the weight of the resistance increases higher movement velocities and decreased movement times result. (from google)
Explanation: hope this helps! :)
Answer:
A) coenzyme A
Explanation:
The NADH and FADH₂ are the energy rich molecules which are formed in the processes like glycolysis, TCA cycle and the fatty acid oxidation as they contain pair of electrons which have very high transfer potential.
As a result of the energy produced when these molecules transfer their electrons to the oxygen , ATP is generated by a series of electron carriers which collectively is called electron transport chain (ETC).
<u>The components of chain include Fe–S centers, Non-heme, FMN, coenzyme Q, and cytochromes .
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The energy derived from the transfer of electrons is used to pump the protons across mitochondrial membrane.
As a result, an electrochemical gradient is generated which results in some energy which is then harnessed by the ATP synthase to form ATP.
Answer:
Explanation:
<u>1. Number of moles of gasoline</u>
a) Convert 60.0 liters to grams
- mass = 0.77kg/liter × 60.0 liter = 46.2 kg
- 46.2kg × 1,000g/kg = 46,200g
b) Convert 46,200 grams to moles
- molar mass of C₈H₁₈ = 114.2 g/mol
- number of moles = mass in grams / molar mass
- number of moles = 46,200g / (114.2 gmol) = 404.55 mol
<u>2. Number of moles of carbon dioxide, CO₂ produced</u>
a) Balanced chemical equation (given):
- C₈H₁₈ (l) + ²⁵/₂ O₂ (g) → 8 CO₂ (g) + 9 H₂O (g)
b) mole ratio:
- 1 mol C₈H₁₈ / 8 mol CO₂ = 404.55 mol C₈H₁₈ / x
Solve for x:
- x = 404.55mol C₈H₁₈ × 8 mol CO₂ / 1mol C₈H₁₈ = 3,236.4 mol CO₂
<u> 3. Convert the number of moles of carbon dioxide to volume</u>
Use the ideal gas equation:
- R = 0.08206 (mol . liter)/ (K . mol)
Substitute and compute:
- V =3,236.4 mol × 0.08206 (mol . liter) / (K . mol) 298.15K / 1 atm
Round to two significant figures (because the density has two significant figures): 79,000 liters ← answer
Answer:
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Explanation:
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In the above-given equation, we can see from 
, of both oxidant 
as well as the reactant were connected. however, weight decreases oxidant and reduction component concentration only with volume and the both of the half cells by the very same factor and each other suspend
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