Answer:
The partial pressure of CO2 is 712,8 in torr
Explanation:
Molar fraction = Pressure in a compound / Total Pressure
Molar fraction H20 = 21,2 / 734 = 0,0288
Sum of molar fraction in a sample = 1
1 - 0,0288 = 0,9712 (molar fraction of CO2)
Molar fraction CO2 = Pressure CO2 / Total pressure
0,9712 . 734 = Pressure CO2
712,8 =Pressure CO2
Answer:6M
Explanation:
From Co= 10pd/M
Where Co= molar concentration of raw acid
p= percentage by mass of raw acid=20%
d= density of acid=1.096g/cm3
M= molar mass of acid=36.5
Co= 10×20×1.096/36.5=6M
The weight in grams = 7.93 g
Given volume = 2.00
Given density = 0.242 g/
We need to find the Mass(weight) in grams.
To find the weight in grams we need to keep in mind that the volume and density must use the same volume unit for cancellation. So that the volume units will cancel out, leaving only the mass units.
The unit of given volume is
and unit of volume in density is
, so first we need to change the unit of volume from
to
so that the volume units will cancel out, leaving only the mass units.
1
= 16.39
(given conversion)

units get cancel out leaving the
unit.

Mass = Density X Volume.
Density = 0.242 g/
and Volume = 32.78 

Mass = 7.93 grams (g)
Answer:
D. 91.98K
Explanation:
The General Gas Law equation is given by,

From the question,
the initial pressure,

the initial volume,

the final temperature,

the final pressure,

the final volume,

Making

the subject of the expression, we obtain

By substitution,


Hence the initial temperature was 91.98 K