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ruslelena [56]
2 years ago
12

Dehydrohalogenation of tert-pentyl bromide at higher temperatures will produce 2-methyl-1-butene as the chief product when

Chemistry
1 answer:
salantis [7]2 years ago
6 0

I'm going to suppose you want the adjusted chemical reaction, using the formulas of the compounds. You can see it in the image attached.

You might be interested in
How many moles of CaC2 are needed to react completely with 45.0g H2O?
sertanlavr [38]

Answer:

In order to react with 45 g of water 1.25 moles of CaC₂ are required.

Explanation:

Given data:

Moles of CaC₂ needed = ?

Mass of water = 45.0 g

Solution:

Chemical equation:

CaC₂ + 2H₂O      →      C₂H₂ + Ca(OH)₂

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 45 g/ 18 g/mol

Number of moles = 2.5 mol

Now we will compare the moles of water and CaC₂ from balance chemical equation:

                     H₂O             :             CaC₂

                       2                :                1

                     2.5              :             1/2×2.5 =1.25 mol

In order to react with 45 g of water 1.25 moles of CaC₂ are required.

6 0
2 years ago
an underground explosion generates sound waves that travel through solid rock, then through a lake and then air. describe how th
DIA [1.3K]

Answer: sound can slow down, so when it travels through all of that it's muffled and kind of blocked. sound travels at 332 metres per second so it's hard to stop the sound

Explanation:

7 0
2 years ago
The incomplete table below shows selected characteristics of gas laws.
Elenna [48]

Explanation :

In the given case different law related to gas is given. The attached figure shows the required solution.

Boyle's law states that the pressure is inversely proportional to the volume of the gas i.e.

P\propto \dfrac{1}{V}

PV=k

k is a constant.

Charle's law states that the volume of directly proportional to the temperature of the gas.

V\propto T

V=kT

Combined gas law is the combination of the pressure, volume and the temperature of the gas i.e.

\dfrac{PV}{T}=k

Hence, this is the required solution.

6 0
2 years ago
Read 2 more answers
How do both plants and animals fight pathogens. A.both have a protective outer layer B.both have an antigen-antibody response C.
ira [324]
<span>Both plants and animals fight pathogens is because both have an ant. </span><span>The answer is B. 

P</span>athogens is <span>a bacterium, virus, or other microorganism that can cause disease.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
</span>
3 0
2 years ago
Read 2 more answers
BH+ClO4- is a salt formed from the base B (Kb = 1.00e-4) and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, w
Len [333]

Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is <u>5.44</u>

Explanation:

Given: The base dissociation constant: K_{b} = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: K_{w} = 1 × 10⁻¹⁴

<em><u>The acid dissociation constant </u></em>(K_{a})<em><u> for the weak acid (BH⁺) can be calculated by the equation:</u></em>

K_{a}. K_{b} = K_{w}    

\Rightarrow K_{a} = \frac{K_{w}}{K_{b}}

\Rightarrow K_{a} = \frac{1\times 10^{-14}}{1\times 10^{-4}} = 1\times 10^{-10}

<em><u>Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:</u></em>

Reaction involved: BH⁺  +  H₂O  ⇌  B  +  H₃O+

Initial:                     0.1 M                    x         x            

Change:                   -x                      +x       +x

Equilibrium:           0.1 - x                    x         x

<u>The acid dissociation constant: </u>K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}

\Rightarrow K_{a} = \frac{x^{2}}{0.1 - x}

\Rightarrow 1\times 10^{-10} = \frac{x^{2}}{0.1 - x}

As, x

\Rightarrow 0.1 - x = 0.1

\therefore 1\times 10^{-10} = \frac{x^{2}}{0.1 }

\Rightarrow x^{2} = (1\times 10^{-10})\times 0.1 = 1\times 10^{-11}

\Rightarrow x = \sqrt{1\times 10^{-11}} = 3.16 \times 10^{-6}

<u>Therefore, the concentration of hydrogen ion: x = 3.6 × 10⁻⁶ M</u>

Now, pH = - ㏒ [H⁺] = - ㏒ (3.6 × 10⁻⁶ M) = 5.44

<u>Therefore, the pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44</u>

5 0
1 year ago
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