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Natasha_Volkova [10]
2 years ago
14

How many moles of CaC2 are needed to react completely with 45.0g H2O?

Chemistry
1 answer:
sertanlavr [38]2 years ago
6 0

Answer:

In order to react with 45 g of water 1.25 moles of CaC₂ are required.

Explanation:

Given data:

Moles of CaC₂ needed = ?

Mass of water = 45.0 g

Solution:

Chemical equation:

CaC₂ + 2H₂O      →      C₂H₂ + Ca(OH)₂

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 45 g/ 18 g/mol

Number of moles = 2.5 mol

Now we will compare the moles of water and CaC₂ from balance chemical equation:

                     H₂O             :             CaC₂

                       2                :                1

                     2.5              :             1/2×2.5 =1.25 mol

In order to react with 45 g of water 1.25 moles of CaC₂ are required.

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A sample of sodium reacts completely with 0.355 kg of chlorine, forming 585 g of sodium chloride. What mass of sodium reacted?
Kay [80]

Answer:

The mass of sodium that reacted is 230 grams

Explanation:

The balance equation of the reaction is first written .

sodium = Na

Chlorine = Cl2

sodium chloride = NaCl

2Na + Cl2 → 2NaCl

from the balance equation we calculate the molar mass involve in the reaction

Molar mass of sodium from the equation = 23(2) = 46 g

molar mass of sodium chloride from the eqaution = 23 × 2 + 35.5 × 2 = 46 + 71 = 117 g

If 46g of sodium is in 117 g of sodium chloride

? gram will be in 585 g of sodium chloride

cross multiply

46 × 585/117 = 26910/117  = 230 g

The mass of sodium that reacted is 230 grams

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An atom of beryllium (m = 8.00 u) splits into two atoms of helium (m = 4.00 u) with the release of 92.2 kev of energy. if the or
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4 0
2 years ago
Read 2 more answers
You have 49.8 g of O2 gas in a container with twice the volume as one with CO2 gas. The pressure and temperature of both contain
IrinaVladis [17]

Answer:

34.2 g is the mass of carbon dioxide gas one have in the container.

Explanation:

Moles of O_2:-

Mass = 49.8 g

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{49.8\ g}{32\ g/mol}

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Since pressure and volume are constant, we can use the Avogadro's law  as:-

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Given ,  

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n₁ = ?

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Using above equation as:

\frac {V_1}{n_1}=\frac {V_2}{n_2}

\frac {V_1}{n_1}=\frac {2\times V_1}{1.55625}

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Molar mass of CO_2 = 44.0 g/mol

Mass of CO_2 = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g

<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>

5 0
2 years ago
What is the 2s in 42,256
MissTica

42,256 = 2,000

42,256 = 200

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5 0
2 years ago
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