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Gwar [14]
2 years ago
5

The alcohol content of hard liquor is normally given in terms of the "proof," which is defined as twice the percentage by volume

of ethanol (C2H5OH) present. Calculate the number of grams of alcohol present in 1.00 L of 48-proof gin. The density of ethanol is 0.798 g/mL.
Chemistry
1 answer:
goldenfox [79]2 years ago
7 0

Answer:

m C2H5OH = 191.52 g

Explanation:

  • proof ≡ (2)(%v/v C2H5OH)

∴ %v/v C2H5OH = ( v C2H5OH / v sln)×100

⇒ 48 proof = (2) (%v/v C2H5OH)

⇒ 48/2 = %v/v C2H5OH

⇒ 24 = %v/v C2H5OH

⇒ 24/100 = v C2H5OH / v sln = 0.24

∴ v sln (gin) = 1.00 L

⇒ v C2H5OH = ( 0.24 )( 1.00 L )

⇒ v C2H5OH = 0.24 L = 240 mL

⇒ m C2H5OH = (240 mL)(0.798 g/mL)

⇒ m C2H5OH = 191.52 g

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Which of the following statements is true about the following reaction?
MAVERICK [17]

The correct reaction equation is:

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Answer:

b) 1 mole of water is produced for every mole of carbon dioxide produced.

Explanation: <u>CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.</u>

a) <u>22.4 L of CO_{2} gas</u> is produced only when <u>\frac{22.4}{3} L of  C_{6}H_{8}O_{7}</u> is reacted with 22.4 L of NaHCO_{3}. So it is wrong.

b) Since in the chemical equation the stoichiometric coefficient of CO_{2}  and H_{2}O are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. <u>Therefore it is correct option.</u>

c)  6.02\times 10^{23} molecules is equal 1 mole of Na_{3}C_{6}H_{5}O_{7} if produced then 3 moles of NaHCO_{3} is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of H_{2}O (<em>Molecular Weight of water is 18 g</em>) is produced when 3 moles of NaHCO_{3} is used but in this option only one mole of NaHCO_{3} is given. So it is wrong.

8 0
2 years ago
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Answer:

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The given reaction can be written as summation of the following reaction-

2NO+Br_{2}\rightleftharpoons 2NOBr

N_{2}+O_{2}\rightleftharpoons 2NO

......................................................................................

N_{2}+O_{2}+Br_{2}\rightleftharpoons 2NOBr

Equilibrium constant of this reaction is given as-

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Answer:

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