The molarity (M) of the acid in the lake water is 
.
<u>Explanation:</u>
In order to estimate the concentration of a solution in molarity, then the total number of moles of the solute is divided by the total volume of the solution.
According to the given information, the formula will be applied for calculating molarity (M) of the acid in the lake water is :
Here;
are molarity of acid in the lake water and base solution respectively.
are volume of sample in the lake water and base solution respectively.
Given values are as follows:
Putting these values in above equation :
Therefore, the molarity (M) of the acid in the lake water is .
Ammonium carbonate will form 3 moles of ions.
Methyl alcohol will form 0 moles of ions.
Methane will form 0 moles of ions.
Aluminum sulfite will form 3 moles of ions.
Hydrobromic acid will form 2 moles of ions.
Explanation:
One mole of ammonium carbonate will form 3 moles of ions when dissolved in water.
(NH₄)₂CO₃ (s) + H₂O (l) → 2 NH₄⁺ (aq) + CO₃²⁻ (aq) + H₂O (l)
One mole of methyl alcohol will form 0 moles of ions when dissolved in water.
(actually it form ions because of its acidic behavior but they are at the order of 10⁻⁷ moles, however in the framework of this question we may say that there are none)
One mole of methane will form 0 moles of ions when dissolved in water.
Methane does not react with water (in normal conditions) so will not form ions.
One mole of aluminum sulfite will form 3 moles of ions when dissolved in water.
Al₂SO₃ (s) + H₂O (l) → 2 Al₃⁺ (aq) + SO₃²⁻ (aq) + H₂O (l)
One mole of hydrobromic acid will form 2 moles of ions when dissolved in water.
HBr (l) + H₂O (l) → Br⁻ (aq) + H₃O⁺ (aq)
Learn more about:
solvation of ions
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Answer:The change in temperature of the gas mixture is -68.44 K.
Explanation:
1. Temperature of the bottle when only helium gas was present :T
Pressure inside the container =P= 1.83 atm
Volume of the container = V = 2.50 L
Moles of helium gas = n = 0.458 moles
Using an Ideal gas equation:
2. Temperature of the bottle when argon gas is added into the container:T'
Pressure inside the container = P' =2.05 atm
Volume of the container = V = 2.50 L
Moles of helium gas = n' = 0.458 mol + 0.713 mol = 1.171 mol
The change in temperature will be given as:
Final temperature = Initial temperature:T' - T
53.37 k - 121.81 K = -68.44 K
The change in temperature of the gas mixture is -68.44 K.
That is the balanced chemical equation.
Before reaction,
milli-moles of Mg(OH)2 = 100 x 0.02 = 2
milli-moles of HNO3 = 100 x 0.05 = 5
After reaction:
Mg(OH)2 is limiting reagent. It will react completely leaving some HNO3 behind.
milli-moles of HNO3 react = 2 x coefficient of HNO3 = 2 x 2 = 4
milli-moles of HNO3 left = 5 -4 = 1
Now, total volume = 100+ 100 = 200 mL
It is asked for hydronium ion concentration, which is basically hydrogen ion conc.
1 HNO3 will dissociate to give 1 H+ ion.
so, milli-moles of H+ = 1
So, concentration of H+ or hydronium(H3O+) = 1 / 200 = 0.005
Answer:
That is alot to answer so i am not sure could answer this it is too hard maybe you could break it down for me cause this alot
Explanation:
- I wish i knew
- Its too much
- I don't know this kind of chemistry
- if you have another chemistry question i could answer plz let me know
- cause this too hard
