Answer:
391.462 g
Explanation:
First, let's calculate the total mass of the solution by the definition of density (d)
d = m/V, where <em>m</em> is the mass in gram and <em>V</em> the volume in mL. So for the given solution
1.285 = m/800
m = 1028 g
The mass of sulfuric acid will be:
0.3808x1028 = 391.462 g
The density of a substance can simply be calculated by
dividing the mass by the volume:
density = mass / volume
Therefore calculating for the density since mass and volume
are given:
density = 46.0 g / 34.6 mL
density = 1.33 g / mL
If there are options, they are b, c, and d. I've done this question in class before :)
Answer is: 6.022·10²² molecules of glucose.
c(glucose) = 100 mM.
c(glucose) = 100 · 10⁻³ mol/L.
c(glucose) = 0.1 mol/L; concentration of glucose solution.
V(glucose) = 1 L; volume of glucose solution.
n(glucose) = c(glucose) · V(glucose).
n(glucose) = 0.1 mol/L · 1 L.
n(glucose) = 0.1 mol; amount of substance.
N(glucose) = n(glucose) · Na (Avogadro constant).
N(glucose) = 0.1 mol · 6.022·10²³ 1/mol.
N(glucose) = 6.022·10²².
The molarity is the number of moles in 1 L of the solution.
The mass of NH₃ given - 2.35 g
Molar mass of NH₃ - 17 g/mol
The number of NH₃ moles in 2.35 g - 2.35 g / 17 g/mol = 0.138 mol
The number of moles in 0.05 L solution - 0.138 mol
Therefore number of moles in 1 L - 0.138 mol / 0.05 L x 1L = 2.76 mol
Therefore molarity of NH₃ - 2.76 M
