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marusya05 [52]
2 years ago
11

Assume the following substances are soluble in water.

Chemistry
1 answer:
solmaris [256]2 years ago
8 0

Ammonium carbonate will form 3 moles of ions.

Methyl alcohol will form 0 moles of ions.

Methane will form 0 moles of ions.

Aluminum sulfite will form 3 moles of ions.

Hydrobromic acid will form 2 moles of ions.

Explanation:

One mole of ammonium carbonate will form 3 moles of ions when dissolved in water.

(NH₄)₂CO₃ (s) + H₂O (l) → 2 NH₄⁺ (aq) + CO₃²⁻ (aq) + H₂O (l)

One mole of methyl alcohol will form 0 moles of ions when dissolved in water.

(actually it form ions because of its acidic behavior but they are at the order of 10⁻⁷ moles, however in the framework of this question we may say that there are none)

One mole of methane will form 0 moles of ions when dissolved in water.

Methane does not react with water (in normal conditions) so will not form ions.

One mole of aluminum sulfite will form 3 moles of ions when dissolved in water.

Al₂SO₃ (s) + H₂O (l) → 2 Al₃⁺ (aq) + SO₃²⁻ (aq) + H₂O (l)

One mole of hydrobromic acid will form 2 moles of ions when dissolved in water.

HBr (l) +  H₂O (l) → Br⁻ (aq) + H₃O⁺ (aq)

Learn more about:

solvation of ions

brainly.com/question/5384053

#learnwithBrainly

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To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K
Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S

Thus, by combining them, we obtain:

-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}

Which is related to the general line equation:

y=mx+b

Whereas:

y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0
2 years ago
What is the enthalpy for reaction 1 reversed?reaction 1 reversed: N2O4→N2 + 2O2
Nutka1998 [239]

Answer:

8kJ/mol

Explanation:

since the forward reaction is -8kJ/mol, the backward reaction has the same enthalphy but reversed

7 0
1 year ago
Procaine hydrochloride ( = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which has a
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Procaine hydrochloride ( = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which has a density of 1.1066 g/ml.

molarity = Moles of solute /  volume of solution

          Molarity = m d / [ 1 + (mW / 1000)]

Molarity = 4.666 X 1.1066 / [ 1 + (4.666 X 272.77 / 1000)]

Molarity =  5.16 / 2.272= 2.271 M

5 0
2 years ago
Read 2 more answers
At a given set of conditions 241.8 kJ of heat is released when one mole of H2O forms from its elements. Under the same condition
yan [13]

Answer:

44Kj

Explanation:

These are the equations for the reaction described in the question,

Vaporization which can be defined as transition of substance from liquid phase to vapor

H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H

-241.8kj -------eqn(1)

H2(g)+ 1/2 O2(g) ------>H2O(l).

Δ H =285.8kj ---------eqn(2)

But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as

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But the equation from eqn(2) the eqn does go with vaporization so we can re- write as

H2O ------> H2(g)+ 1/2 O2(g)

Δ H= 285.8kj ---------------eqn(4)

To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)

Δ H=285.8kj +(-241.8kj)= 44kj

5 0
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Which traits does the common garter snake have that might be adaptive for the environment where it lives?
Licemer1 [7]

Answer:

As the garter snake can be found almost in any kind of habitat, what makes them be able to survive in any environment include:

1. They hibernate to increase their chances of survival in unfavorable weather conditions.

2. They can blend with the background of any environment especially grass to escape being eaten.

3. They produce an odor that is usually unpleasant especially when about to be attacked.

Explanation:

The garter snakes are distinguished by the three stripes running the length of their body and can often be found in forests, places that are even close to water bodies, and almost any place, even in holes.

 

           

4 0
1 year ago
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