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1 year ago

Which traits does the common garter snake have that might be adaptive for the environment where it lives?

Chemistry

1 answer:

Licemer1 [7]1 year ago

4 0

Answer:

As the garter snake can be found almost in any kind of habitat, what makes them be able to survive in any environment include:

1. They hibernate to increase their chances of survival in unfavorable weather conditions.

2. They can blend with the background of any environment especially grass to escape being eaten.

3. They produce an odor that is usually unpleasant especially when about to be attacked.

Explanation:

The garter snakes are distinguished by the three stripes running the length of their body and can often be found in forests, places that are even close to water bodies, and almost any place, even in holes.

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The temperature of the carbon dioxide atmosphere near the surface of venus is 475°c. calculate the average kinetic energy per mo

harkovskaia [24]

Answer: 9330 j/mol

The temperature of the gas is 475 ° Celcius which is equal to: 475 +273= 748 °K. The formula for kinetic energy of individual atoms would be

K= 3/2 * kB * T
If kB is 1.38 * 10^-23 J/K and 1 mol is made from 6.02*10^23 molecule, then the kinetic energy of 1 mol CO2 would be:
K= 3/2 * kB * T
K= 3/2 * 1.38 * 10^-23 * 748 * 6.02 *10^23 =9324 J/mol

8 0

1 year ago

According to the quantum-mechanical model for the hydrogen atom, which electron transition produces light with the longer wavele

LekaFEV [45]

Answer:

Explanation:

The main task here is that there are some missing gaps in the above question that needs to be filled with the appropriate answers. So, we are just going to do rewrite the answer below as we indicate the missing gaps by underlining them and making them in bold format.

SO; In the quantum-mechanical model of the hydrogen atom.

As the n level increases. the energy increases and thus levels are closer to each other. Therefore, the transition 3p→2s would have a greater energy difference than the transition from 4p→3p.

$Energy \ and \ wavelength \ are \ inversely \ proportional , \ so \ the \ \mathbf{ 4p\to 3p} \ transition \ would$ $produce \ a \ longer \ wavelength.$

3 0

2 years ago

Determine whether the stopcock should be completely open, partially open, or completely closed for each activity involved with t

densk [106]

Answer:

Close to the calculated endpoint of a titration - Partially open

At the beginning of a titration - Completely open

Filling the buret with titrant - Completely closed

Conditioning the buret with the titrant - Completely closed

Explanation:

'Titration' is depicted as the process under which the concentration of some substances in a solution is determined by adding measured amounts of some other substance until a rection is displayed to be complete.

As per the question, the stopcock would remain completely open when the process of titration starts. After the buret is successfully placed, the titrant is carefully put through the buret in the stopcock which is entirely closed. Thereafter, when the titrant and the buret are conditioned, the stopcock must remain closed for correct results. Then, when the process is near the estimated end-point and the solution begins to turn its color, the stopcock would be slightly open before the reading of the endpoint for adding the drops of titrant for final observation.

3 0

2 years ago

Ron and Hermione begin with 1.50 g of the hydrate copper(II)sulfate ∙ x-hydrate (CuSO4 ∙ xH2O), where x is an integer. Part of t

Gnom [1K]

Answer:

The unknown integer X in the formula is 5.

Explanation:

1) Data:

a) Mass of CuSO₄ ∙ XH₂O = 1.50 g

b) Mass of CuSO₄ = 0.96

c) X = ?

2) Additional needed data:

a) Molar Mass of CuSO₄ = 159,609 g/mol

b) Molar mass of H₂O = 18,01528 g/mol

3) Chemical principles and formulae used:

a) Law of conservation of mass

b) Molar mass = mass in grams / number of moles = m / n

4) Solution:

a) Law of conservation of mass:

Mass of CuSO₄ ∙ XH₂O = mass of CuSO₄ + mass of H₂O

1.50g = 0.96g + mass of H₂O ⇒ mass of H₂O = 1.50g - 0.96g = 0.54g

b) Moles

n = m / molar mass

CuSO₄: n = 0.96g / 159.609 g/mol = 0.0060 mol

H₂O: 0.54g / 18.01528 g/mol = 0.030 mol

c) Proportion:

Divide both mole amounts by the least of the two numbers, i.e. 0.0060

CuSO₄: 0.0060 / 0.0060 = 1

H₂O: 0.030 mol / 0.0060 = 5

Then, the ratio of CuSO₄ to H₂O is 1 : 5 and the chemical formula is:

CuSO₄ . 5H₂O.

Hence, the value of X is 5.

5 0

2 years ago

Read 2 more answers

An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object?

dedylja [7]

Answer:

The mass of object is 0.5 Kg.

Explanation:

Given data:

Acceleration of object = 12.0 m/s²

Force on object = 6.0 N

Mass of object = ?

Solution:

Formula:

F = m×a

F = force

m = mass

a = acceleration

Now we will put the values in formula.

6.0 N = m × 12.0 m/s²

m = 6.0 N / 12.0 m/s²

( N = kg.m/s²)

m = 0.5 kg

The mass of object is 0.5 Kg.

5 0

2 years ago