answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anygoal [31]
1 year ago
15

Determine whether the stopcock should be completely open, partially open, or completely closed for each activity involved with t

itration.
Close to the calculated endpoint of a titration ________
At the beginning of a titration _______
Filling the buret with titrant ________
Conditioning the buret with titrant _______
Chemistry
1 answer:
densk [106]1 year ago
3 0

Answer:

Close to the calculated endpoint of a titration - <u>Partially open</u>

At the beginning of a titration - <u>Completely open</u>

Filling the buret with titrant - <u>Completely closed</u>

Conditioning the buret with the titrant - <u>Completely closed</u>

Explanation:

'Titration' is depicted as the process under which the concentration of some substances in a solution is determined by adding measured amounts of some other substance until a rection is displayed to be complete.

As per the question, the stopcock would remain completely open when the process of titration starts. After the buret is successfully placed, the titrant is carefully put through the buret in the stopcock which is entirely closed. Thereafter, when the titrant and the buret are conditioned, the stopcock must remain closed for correct results. Then, when the process is near the estimated end-point and the solution begins to turn its color, the stopcock would be slightly open before the reading of the endpoint for adding the drops of titrant for final observation.

You might be interested in
The information below describes a redox reaction. 3 equations: First: upper C r superscript 3 plus (a q) plus 2 upper C l supers
Marrrta [24]

Answer:

A.

Explanation:

I just took the quiz.

7 0
2 years ago
How many moles are in 987 grams of : Ra(OH)2
sergejj [24]
Your answer is 3.80 moles
8 0
1 year ago
Read 2 more answers
Calculate the number of atoms in 2.5 mol manganese.
Leokris [45]

Answer:

1.5 × 10²⁴ atoms Mn

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

2.5 mol Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />2.5 \ mol \ Mn(\frac{6.022 \cdot 10^{23} \ atoms \ Mn}{1 \ mol \ Mn} ) = 1.5055 × 10²⁴ atoms Mn

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

1.5055 × 10²⁴ atoms Mn ≈ 1.5 × 10²⁴ atoms Mn

6 0
1 year ago
Use the following structures of amino acids to answer the questions below. Note that the difference in the structures (the side
alexira [117]
In a positively charged column, Asparate will travel the farthest followed by Threonine, Leucine and Lysine.
7 0
1 year ago
The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that
kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is 1.1\times 10^6 M.

HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)

This value indicates that

A. CN^- is a stronger base than ONO^-

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is ONO^-

D. The conjugate acid of CN- is HCN

Answer: A. CN^- is a stronger base than ONO^-

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When K_{p}>1; the reaction is product favoured.

When K_{p}; ; the reaction is reactant favored.

When K_{p}=1; the reaction is in equilibrium.

As, K_p>>1, the reaction will be product favoured and as it is a acid base reaction where HONO acts as acid by donating H^+ ions and CN^- acts as base by accepting H^+

Thus HONO is a strong acid thus ONO^- will be a weak conjugate base and CN^- is a strong base which has weak HCN conjugate acid.

Thus the high value of K indicates that CN^- is a stronger base than ONO^-

7 0
1 year ago
Other questions:
  • Nonmetals rarely lose electrons in chemical reactions because?
    11·1 answer
  • The hydrogen bonding in water creates ________, a cohesive force that enables one to slightly overfill a glass with water or all
    12·1 answer
  • Robert places a piece of magnesium metal (Mg) into a test tube of hydrochloric acid (HCl). The magnesium begins to bubble and fi
    15·2 answers
  • Cacodyl, which has an intolerable garlicky odor and is used in the manufacture of cacodylic acid, a cotton herbicide, has a mass
    5·1 answer
  • Which of the following statements is true about the following reaction?
    15·2 answers
  • A gas sample enclosed in a rigid metal container at room temperature (20.0∘C∘C) has an absolute pressure p1p1p_1. The container
    13·1 answer
  • 7.47 Two atoms have the electron configurations 1s22s22p6 and 1s22s22p63s1. The first ionization energy of one is 2080 kJ/mol an
    6·1 answer
  • Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produ
    14·1 answer
  • ....Which is the best classification for West Nile virus?
    11·2 answers
  • Calcite is mineral that is found in limestone and marble. A model of the extended structure of calcite is
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!