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anygoal [31]
2 years ago
15

Determine whether the stopcock should be completely open, partially open, or completely closed for each activity involved with t

itration.
Close to the calculated endpoint of a titration ________
At the beginning of a titration _______
Filling the buret with titrant ________
Conditioning the buret with titrant _______
Chemistry
1 answer:
densk [106]2 years ago
3 0

Answer:

Close to the calculated endpoint of a titration - <u>Partially open</u>

At the beginning of a titration - <u>Completely open</u>

Filling the buret with titrant - <u>Completely closed</u>

Conditioning the buret with the titrant - <u>Completely closed</u>

Explanation:

'Titration' is depicted as the process under which the concentration of some substances in a solution is determined by adding measured amounts of some other substance until a rection is displayed to be complete.

As per the question, the stopcock would remain completely open when the process of titration starts. After the buret is successfully placed, the titrant is carefully put through the buret in the stopcock which is entirely closed. Thereafter, when the titrant and the buret are conditioned, the stopcock must remain closed for correct results. Then, when the process is near the estimated end-point and the solution begins to turn its color, the stopcock would be slightly open before the reading of the endpoint for adding the drops of titrant for final observation.

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You are given a compound with the formula mcl2, in which m is a metal. you are told that the metal ion has 26 electrons. what is
Nookie1986 [14]

Answer:

             Nickle

Explanation:

                  In statement it is given that the metal "M" has a formula "MCl₂" which means it has a charge of +2 as each Chlorine atom has -1 charge. Therefore, it is cleared that this metal has lost 2 electrons and originally it was carrying 28 electrons.

                  After that periodic table is concerned and a metal with 28 atomic number was tracked because a neutral atom with 28 electrons must have 28 protons and protons are infact the atomic number.

                  Hence, in periodic table the metal with 28 atomic number is found to be Nickle.

6 0
2 years ago
In the manufacture of steel, pure oxygen is blown through molten iron to remove some of the carbon impurity. if the combustion o
Schach [20]

In the extraction process of steel, one of the step is purification of the iron used to make the steel. In which pure oxygen is blown on the steel at high temperature so that the carbon percentage present in the steel can be thrown out in the form of gas. The process occurs at high temperature which is called combustion process. The reaction occurs can be shown as- C(s)+O_{2}→CO_{2} (g) + CO (g). In presence of excess oxygen, the produced carbon mono oxide (CO) converts to carbon di-oxide. The reaction is CO(g) + O_{2}(g) → CO_{2} (g). From the density of the evolved gas one could identify the gas. If the gas density is 1.77g/L which is very close to the standard density of CO_{2} i.e. 1.80g/L, the gas is carbon dioxide only.    

8 0
2 years ago
Read 2 more answers
calculate the volume od a CO2 cartridge that has a pressure of 850 PSI at a temperature of 21ºc the cartridge contains 0.273 mol
gladu [14]
Answer is: volume of CO₂ is 0,113 dm³.
Ideal gas law = pV = nRT.
p = 850 PSI = 5860543,6992 Pa.
Psi <span>is the abbreviation of pound per square inch.
T = 21</span>°C = 294,15 K.
n = 0,273 mol.
R = 8,314 J/K·mol.
V = nRT ÷ p
V = 0,273 mol · 8,314 J/K·mol · 294,15 K ÷ 5860543,6992 Pa.
V = 0,00011 m³ = 0,113 dm³.
3 0
2 years ago
A silver sphere has a mass of 5.492 g and a diameter of 10.0 mm. What is the density of silver metal in grams per cubic centimet
Blizzard [7]

Answer:

Explanat\rho=10.5\frac{g}{cm^3}ion:

Hello,

In this case, considering the given diameter which is related to a radius of 5.0 mm and the formula for the calculation of the volume of the sphere, its volume in cubic centimeters (5.00 mm = 0.5 cm) is then:

V=\frac{4}{3} \pi r^3=\frac{4}{3}*\pi*(0.5cm)^3\\\\V=0.524cm^3

In such a way, the density turns out:

\rho =\frac{m}{V} =\frac{5.492g}{0.048m^3} \\\\\rho=10.5\frac{g}{cm^3}

Best regards.

8 0
1 year ago
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mario62 [17]

Answer:

A polysaccharide (n) can be formed by linking several monosaccharides through glycosidic linkages.

Explanation:

Polysaccharides are carbohydrates or complex carbohydrates, where monosaccharides join with glucosidic bonds to form a more complex structure that would be the polysaccharide.

An example of a polysaccharide is starch, or glycogen.

Starch is found in many foods such as potatoes or rice, and glycogen is a form of energy reserve of our organism housed in muscles and liver to fulfill locomotion, physical activity, and other activities that consist of glycolysis.

Polysaccharides are degraded in our body by different stages, and several enzymes unlike monosoccharides or disaccharides, since they have more unions and a more complex structure to disarm in our body and thus assimilate it.

Polysaccharides are also part of animal structures, such as insect shells or nutritional sources, among others.

7 0
2 years ago
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