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Rasek [7]
2 years ago
8

What is the mass in grams of 7.5 x 10^15 atoms of nickel?

Chemistry
2 answers:
satela [25.4K]2 years ago
6 0
Atomic mass Ni = 58.69 a.m.u

58.69 g ----------------- 6.02x10²³ atoms
?? g --------------------- 7.5x10¹⁵ atoms

58.69x (7.5x10¹⁵) / 6.02x10²³

=> 7.31x10⁻⁷ g
vredina [299]2 years ago
5 0

Answer:

The mass of 7,5.10^{15} nickel atoms is 7,34.10^{-7}g grams

Explanation:

We want to know how many grams 7.5.10^{15} nickel atoms equals and we know that one mole of any substance equals 6.021023 atoms

To know how many moles correspond 7.5.10^{15} nickel atoms apply a simple rule of three

6,02.10^{23}  atoms\longrightarrow 1 mol\\7,5.10^{15} atoms\longrightarrow x\\x=\frac{(7,5.10^{15})(1mol) }{6,02.10^23atoms} \\x= 1,25.10^{-8} mol

The constant that relates the mass (grams) and the amount of substance (mol) is the molecular mass of the element The nickel molar mass is 58.69g/mol

to know how many grams of nickel correspond 1,25.10^{-8} mol mol we apply a rule of three simple

1 mol \longrightarrow 58.69 g\\1,25.10^{-8}\longrightarrow x \\x= \frac{(1,25.10^{-8}mol)(58.69g) }{1mol} \\x=7,34.10^{-7}g

The mass of 7,5.10^{15} nickel atoms is 7,34.10^{-7}g grams

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The decomposition of AB given here in this balanced equation 2AB (g)⟶ A2 (g) + B2 (g), has rate constants of 8.58 x 10-9 L/mol s
denis-greek [22]

Answer:

3.24 × 10^5 J/mol

Explanation:

The activation energy of this reaction can be calculated using the equation:

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Where; Ea = the activation energy (J/mol)

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ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

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