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Dmitry_Shevchenko [17]
2 years ago
11

According to the quantum-mechanical model for the hydrogen atom, which electron transition produces light with the longer wavele

ngth: 3p + 2s or 4p + 3p? Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help increases As the n level increases, the energy and thus the levels are each 3p → 2s other. Therefore, the transition would have a greater energy difference than the transition from inversely decreases Energy and wavelength are proportional, so the transition would farther from produce a longer wavelength. 4p + 3p directly closer to
Chemistry
1 answer:
LekaFEV [45]2 years ago
3 0

Answer:

Explanation:

The main task here is that there are some missing gaps in the above question that needs to be filled with the appropriate answers. So, we are just going to do rewrite the answer below as we indicate the missing gaps by underlining them and making them in bold format.

SO; In the quantum-mechanical model of the hydrogen atom.

As the n level increases. the energy <u>increases</u> and thus levels are <u>closer to </u>each other. Therefore, the transition <u>3p→2s</u> would have a greater energy difference than the transition from <u>4p→3p.</u>

Energy \  and \  wavelength  \ are \  inversely \   proportional , \  so \  the \ \mathbf{ 4p\to 3p} \ transition  \ wouldproduce  \ a  \ longer \ wavelength.

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DENIUS [597]
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7 0
2 years ago
Acetaminophen (pictured) is a popular nonaspirin, "over-the-counter" pain reliever. what is the mass % (calculate to 4 significa
77julia77 [94]

Acetaminophen as a chemical formula of C8H9NO2. The molar masses are:

C8H9NO2 = 151.163 g/mol

C = 12 g/mol

H = 1 g/mol

N = 14 g/mol

O = 16 g/mol

 

<span>TO get the mass percent, simply multiply the molar mass of each elements  with the number of the element divide by the molar mass of acetaminophen, that is:</span>

%C = [(12 * 8) / 151.163] * 100% = 63.50%

%H = [(1 * 9) / 151.163] * 100% = 5.954%

%N = [(14 * 1) / 151.163] * 100% = 9.262%

<span>%O = [(16 * 2) / 151.163] * 100% = 21.17% </span>

8 0
2 years ago
Radon (Rn) is the heaviest and the only radioactive member of Group 8A(18), the noble gases. It is a product of the disintegrati
xeze [42]

Answer:

V=9.89x10^{-7}\frac{L}{day}

Explanation:

Hello,

On the attached document, you will find the procedure regarding the required volume. At first, it is necessary to know atoms by day produced, by using a rule of three. Subsequently, we compute the moles per day and finally the volume via the ideal gas equation at STP.

Best regards.

4 0
2 years ago
Read 2 more answers
How many particles would be found in a 1.224 g sample of K2O
lbvjy [14]

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

= 74g per mol

number of moles in the sample= 1.224/ 74

=0.1654

Number of particles in 1 mole=6.0221409*10^23

Number of particles= 0.01654*6.0221409*10^23

=9.96*10^21

4 0
2 years ago
Read 2 more answers
Calculate the molar mass of a gas at 388 torr and 45°c if 206 ng of gas occupies 0.206 ul. (
Dmitrij [34]
To make our solution more systematic, let's convert all units that is consistent with the units of R which is 0.0821 L-atm/mol-K.

For pressure: 760 torr = 1 atm
388 torr * 1 atm/760 torr = 0.5105 atm

For volume, 1 μL = 10⁻⁶ L
0.206 μL * 10⁻⁶ L/1 μL = 2.06×10⁻⁷ L

For temperature,
T = 45 + 273 = 318 K

For mass, 1 ng = 10⁻⁹ g
206 ng * 10⁻⁹ g/1 ng = 2.06×10⁻⁷ g

Assuming ideal gas,

PV=nRT
(0.5105 atm)(2.06×10⁻⁷ L) = n(0.0821 L-atm/mol-K)(318 K)
n = 4×10⁻⁹ mol

Molar mass = Mass/n = 2.06×10⁻⁷ g/4×10⁻⁹ mol
<em>Molar mass = 51.14 g/mol</em>

6 0
2 years ago
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