How many particles would be found in a 1.224 g sample of K2O
2 answers:
Answer:
7.8286×10²¹ particles.
Explanation:
First we need to calculate the total molar mass of the compound, in this case:
Potassium (K) = 39.1 g/mol × 2 = 78.2 +
Oxigen (O) = 16 g/mol × 1 = <u> 16 </u>
Total(K₂O) = 94.2 g/mol
Then, we calculate the number of moles of the compound in the sample, this is done dividing de mass of the sample by the molar mass:
mol = 0.013 moles in our sample.
Finally, we calculate the total number of particles. The costant known as Avogadro number (6.022×10²³) is the number of particles or atoms contained in a mole of any substance. We need to multiply the number of moles by the Avogadro number.
particles = 0.013 mol × (6.022×10²³ particles/mol) = 7.8286×10²¹ particles.
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Answer:
a. 123.9°C
b.
c.
Explanation:
Hello, I'm attaching a picture with the numerical development of this exercise.
a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.
b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.
c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.
** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.
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