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natta225 [31]
2 years ago
8

Do you think that solids can undergo convection? explain

Chemistry
1 answer:
3241004551 [841]2 years ago
3 0
No. Solids by definition undergo conduction and only fluids can undergo convection.
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What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an
Mandarinka [93]

Answer: The empirical formula of the compound is Fe_1S_1O_4

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

Percentage of iron in a compound = 36.76 %

Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

Mass of iron in 100 g of compound = 36.76 g

Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

Moles of iron=\frac{36.76 g}{55.84 g/mol}=0.658 mol

Moles of sulfur=\frac{21.11 g}{32.06 g/mol}=0.658 mol

Moles of oxygen=\frac{42.13 g}{16 g/mol}=2.633 mol

Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

For Iron element = \frac{0.658 mol}{0.658 mol}=1

For sulfur element = \frac{0.658 mol}{0.658 mol}=1

For oxygen element = \frac{2.633 mol}{0.658 mol}=4.001\approx 4

So, the empirical formula of the compound is Fe_1S_1O_4

4 0
1 year ago
Read 2 more answers
What is the hydronium ion concentration of a solution whose pH is 7.30
Assoli18 [71]
[ H₃O⁺] = 10 ^ - pH

[ H₃O⁺ ] = 10 ^ - 7.30

[ H₃O⁺ ] = 5.011 x 10⁻⁸ M

hope this helps!
6 0
1 year ago
Given the following data, calculate the densities of a carbon-14 nucleus and a carbon-14 atom. Particle Mass Electron kg Proton
Harman [31]
When it goes bioom bing bong bang pew pew pew yeauae right?
5 0
2 years ago
How many grams of NH3 are needed to provide the same number of molecules as in 0.35 g of SF6 ?
Strike441 [17]

Answer:

<u />

  • <u>There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.</u>

<u />

Explanation:

Using the molar mass of the chemical formula SF₆ you can find the number of moles of molecules in 0.35 g of such substance. Then, using the molar mass of NH₃, you can find mass in grams corresponding to the same number of molecules.

<u>1. Find the molar mass of SF₆:</u>

Atom   atomic mass          number of atoms   total mass in 1 mole

S           32.065 g/mol                     1                                       32.065 g

F            18.998 g/mol                     6                 6 × 18.998 = 113.988 g

                                                                               =====================

                                                          molar mass of SF₆ =    146.053 g/mol

<u>2. Find the number of moles in 0.35 g of SF₆:</u>

  • number of moles = mass in grams / molar mass
  • number of moles = 0.35 g / 146.053 g / mol = 0.0024 mol

<u>3. Find the molar mass of NH₃:</u>

Atom   atomic mass          number of atoms   total mass 1 mole                

N           14.007 g/mol                     1                                       14.007 g

H             1.008 g/mol                    3               3 × 1.008 g = 113.988 g

                                                                               =====================

                                                         molar mass of NH₃ =    17.031 g/mol

<u />

<u>4. Find the mass in 0.0024 mol of NH₃:</u>

  • mass in grams = number of moles × molar mass

  • mass = 0.0024 mol × 17.031 g/mol ≈ 0.041 grams

<u>5. Conclusion: </u>

There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.

6 0
1 year ago
(BONUS QUESTION) In the copper complexes investigated, the water and ammonia molecules act as Lewis bases (electron pair donors)
chubhunter [2.5K]

Answer and explanation:

Water and ammonia molecules acts as Lewis bases. its is clear from the spectrochemical series that NH₃ has stronger field ligand than water

checked thee attached image for additional solutions

3 0
1 year ago
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