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2 years ago

How many grams of NH3 are needed to provide the same number of molecules as in 0.35 g of SF6 ?

Chemistry

1 answer:

Strike441 [17]2 years ago

6 0

Answer:

There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.

Explanation:

Using the molar mass of the chemical formula SF₆ you can find the number of moles of molecules in 0.35 g of such substance. Then, using the molar mass of NH₃, you can find mass in grams corresponding to the same number of molecules.

1. Find the molar mass of SF₆:

Atom atomic mass number of atoms total mass in 1 mole

S 32.065 g/mol 1 32.065 g

F 18.998 g/mol 6 6 × 18.998 = 113.988 g

=====================

molar mass of SF₆ = 146.053 g/mol

2. Find the number of moles in 0.35 g of SF₆:

number of moles = mass in grams / molar mass

number of moles = 0.35 g / 146.053 g / mol = 0.0024 mol

3. Find the molar mass of NH₃:

Atom atomic mass number of atoms total mass 1 mole

N 14.007 g/mol 1 14.007 g

H 1.008 g/mol 3 3 × 1.008 g = 113.988 g

=====================

molar mass of NH₃ = 17.031 g/mol

4. Find the mass in 0.0024 mol of NH₃:

mass in grams = number of moles × molar mass

mass = 0.0024 mol × 17.031 g/mol ≈ 0.041 grams

5. Conclusion:

There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.

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