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valentina_108 [34]
2 years ago
7

What is the molarity of a solution made by dissolving 8.60 g of a solid with a

Chemistry
1 answer:
Dima020 [189]2 years ago
8 0

Answer:

1.43 M

Explanation:

We'll begin by calculating the number of mole of the solid. This can be obtained as follow:

Mass of solid = 8.60 g

Molar mass of solid = 21.50 g/mol

Mole of solid =?

Mole = mass / molar mass

Mole of solid = 8.60 / 21.50

Mole of solid = 0.4 mole

Next, we shall convert 280 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

280 mL = 280 mL × 1 L / 1000 mL

280 mL = 0.28 L

Thus, 280 mL is equivalent to 0.28 L.

Finally, we shall determine the molarity of the solution. This can be obtained as illustrated below:

Mole of solid = 0.4 mole

Volume = 0.28 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.4 / 0.28

Molarity = 1.43 M

Thus, the molarity of the solution is 1.43 M.

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To answer the problem given:

|0.53−4.0| / 4.0 * 100%

= 3.47 / 4.0 * 100%

= 87%

The maximum theoretical percent recovery from the crystallization of 4.0 g of acetanilide from 100 ml of water is 87%. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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Kay [80]

Answer:

-) 3-bromoprop-1-ene

-) 2-bromoprop-1-ene

-) 1-bromoprop-1-ene

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Explanation:

In this question, we can start with the <u>I.D.H</u> (<em>hydrogen deficiency index</em>):

I.D.H~=~\frac{(2C)+2+(N)-(H)-(X)}{2}

In the formula we have 3 carbons, 5 hydrogens, and 1 Br, so:

I.D.H~=~\frac{(2*3)+2+(0)-(5)-(1)}{2}~=~1

We have an I.D.H value of one. This indicates that we can have a cyclic structure or a double bond.

We can start with a linear structure with 3 carbon with a double bond in the first carbon and the Br atom also in the first carbon (<u>1-bromoprop-1-ene</u>). In the second structure, we can move the Br atom to the second carbon (<u>2-bromoprop-1-ene</u>), in the third structure we can move the Br to carbon 3 (<u>3-bromoprop-1-ene</u>). Finally, we can have a cyclic structure with a Br atom (<u>bromocyclopropane</u>).

See figure 1

I hope it helps!

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2 years ago
Calculate the Lattice Energy of KCl(s) given the following data using the Born-Haber cycle: ΔHsublimation K = 79.2 kJ/mol IE1 K
DanielleElmas [232]

Answer:

Explanation:

  The following equation relates to Born-Haber cycle

\triangle H_f = S + \frac{1}{2} B + IE_M - EA_X+ U_L

Where

\triangle H_f is enthalpy of formation

S is enthalpy of sublimation

B is bond enthalpy

IE_M is ionisation enthalpy of metal

EA_X is electron affinity of non metal atom

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Substituting the given values we have

-435.7 = 79.2 + 1/2 x 242.8 + 418.7 - 348 +U_L

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2 years ago
Determine the number of atoms in 1.85 ml of mercury. (the density of mercury is 13.5 g/ml.)
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First step is to get the mass of the mercury:
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Second step is to calculate the number of moles in 24.975 gm:
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