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1 year ago

Chemistry problem H=WQx solve for x

Chemistry

2 answers:

Lana71 [14]1 year ago

8 0

You just have to isolate x, so just divide by WQ on both sides to get:
$x = \frac{H}{WQ}$

DaniilM [7]1 year ago

3 0

Answer:

$\x=\frac{\text{H}}{\text{WQ}}$

Explanation:

The given equation is $\text{H}=\text{WQ}x$

We need to solve the given equation for x.

In order to solve for x, we need to transpose WQ from RHS to LHS.

So, $\text{H}=\text{WQ}x$

Divide both sides of the equation by WQ we get

$\\frac{\text{H}}{\text{WQ}}=\frac{\text{WQ}}{\text{WQ}}x$

So, $\x=\frac{\text{H}}{\text{WQ}}$

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Rank the following compounds in order of reactivity toward nitration with HNO3:_______. thiophene, benzene, 3-methylthiophene, a

siniylev [52]

Answer:

3-methylthiophene > thiophene > benzene > 2-methylfuran

Explanation:

Primarily, five membered heterocyclic aromatic rings undergo nitration at carbon-2. This is because, nitration at carbon-2 leads to the formation of three resonance structures while attack at carbon-3 yields only two resonance structures, hence it is less stabilized.

The presence of a methyl group which donates electrons promotes the stabilization of the cation formed in the nitration of 3-methylthiophene.

2-methylfuran is the least reactive towards nitration because the 2-position has been blocked by a methyl group.

3 0

2 years ago

Magnesium and nitrogen react in a combination reaction to produce magnesium nitride: 3 Mg N2 → Mg3N2 In a particular experiment,

vlada-n [284]

Answer:

The mass of Mg consumed is 21.42g

Explanation:

The reaction is

$3Mg+N_{2}-->Mg_{3}N_{2}$

As per balanced equation, three moles of Mg will react with one mole of nitrogen to give one mole of magnesium nitride.

as given that mass of nitrogen reacted = 8.33g

So moles of nitrogen reacted = $\frac{mass}{molarmass}=\frac{8.33}{28}=0.2975mol$

moles of Mg required = 3 X moles of nitrogen taken = 3X0.2975 = 0.8925mol

Mass of Mg required = moles X molar mass = 0.8925 X 24 = 21.42 g

5 0

2 years ago

Website

vredina [299]

Answer:

volume in L = 0.25 L

Explanation:

Given data:

Mass of Cu(NO₃)₂ = 2.43 g

Volume of KI = ?

Solution:

Balanced chemical equation:

2Cu(NO₃)₂ + 4KI → 2CuI + I₂ + 4KNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 2.43 g/ 187.56 g/mol

Number of moles = 0.013 mol

Now we will compare the moles of Cu(NO₃)₂ with KI.

Cu(NO₃)₂ : KI

2 : 4

0.013 : 4 × 0.013=0.052 mol

Volume of KI:

<em>Molarity = moles of solute / volume in L</em>

volume in L = moles of solute /Molarity

volume in L = 0.052 mol / 0.209 mol/L

volume in L = 0.25 L

6 0

2 years ago

Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding?

Rama09 [41]

Answer:

ions are surrounded by hydrogen ends with positive partial charge. In this way the salt is dissolved in water. Sugar is a molecular compound formed by covalent bonds. In a polar covalent bond, electrons are shared unevenly

Explanation:

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2 years ago

What is the molarity of a HNO3 solution prepared by adding 290.7 mL of water to 350.0 mL of 12.3 M HNO3?

Lisa [10]

Answer:

6.72M of HNO3

Explanation:

In the problem you are diluting the original HNO3 solution by the addition of some water. The final volume is:

290.7mL + 350.0mL = 640.7mL

And you are diluting the solution:

640.7mL / 350.0mL = 1.8306 times

As the original concentration was 12.3M, the final concentration will be:

12.3M / 1.8306 =

5 0

2 years ago