Answer:
Diet: fruit, leaves, bark, stems, seeds, eggs, insects, birds, small to medium sized primates - red tail monkeys, yellow baboons, bushbuck and warthogs.
Environmental Relationship - The chimpanzee keeps the plants it eats short, moves dirt around which helps things living in the dirt, keeps bird and small monkey populations that it eats from overpopulating.
Different biotic and abiotic factors affect why the chimps live where they do. (Spatial Relationships)
Explanation:
Answer:
The answer is Option a, that is "−9kJmole,5kJmole".
Explanation:
Please find the complete question in the attached file.
In the question, it uses the catalyst inside a process, which does not modify the process eigenvalues, however, it decreases the active energy with an enthalpy of -9kJmole, and also the power for activating decreases around 13 to 5 kJ mole, that's why the choice a is correct.
Answer:
Explanation:
Pair 2.50g of O₂ and 2.50g of N₂
The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:
Number of moles = 
Atomic mass of O = 16g and N = 14g
Molar mass of O₂ = 16 x 2 = 32gmol⁻¹
Molar mass of N₂ = 14 x 2 = 28gmol⁻¹
Number of moles of O₂ = 
= 0.078mole
Number of moles of N₂ = 
= 0.089mole
We see that N₂ has the largest number of moles
<h3>Answer:</h3>
Mass = 96.47 g
<h3>
Solution:</h3>
Data Given:
M.Mass = 28.97 g.mol⁻¹
Moles = 3.33 mol
Mass = ??
Formula Used:
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting values,
Mass = 3.33 mol × 28.97 g.mol⁻¹
Mass = 96.4701 g
Rounding to four significant numbers,
Mass = 96.47 g
There are 6.022*10^23 molecules in 1 mole of carbon
So how many will moles will be 7.87*20^7?
Let the required number of moles be ‘x’.
1 mole ———6.022*10^23
x moles———7.87*10^7
(Cross multiplication)
x=7.87*10^7/6.022*10^23
Therefore x=1.3*10^-16
