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34kurt
2 years ago
15

Sulfurous acid, h2so3, breaks down into water (h2o) and sulfur dioxide (so2). if only one molecule of sulfurous acid was involve

d in a chemical reaction, how many sulfur (s) atoms would be in the products?
Chemistry
2 answers:
MA_775_DIABLO [31]2 years ago
7 0

Answer:1 atom of sulfur

Explanation:

devlian [24]2 years ago
6 0

Explanation:

The given reaction equation will be as follows.

  H_{2}SO_{3} \rightarrow H_{2}O + SO_{2}

Now, number of atoms on reactant side are as follows.

  • H = 2
  • S = 1
  • O = 3

Number of atoms on product side are as follows.

  • H = 2
  • S = 1
  • O = 3

Therefore, this equation is balanced since atoms on both reactant and product sides are equal.

Thus, we can conclude that there is one sulfur atom in the products.

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<em>A mixture of ethyl alcohol (molecular mass = 46.1 u) and water (molecular mass = 18.0 u) contains one mole of molecules.</em>

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